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Valentin [98]
2 years ago
10

Find the slope of (-14, -1),(-5,5)

Mathematics
1 answer:
avanturin [10]2 years ago
5 0

Answer: The slope is 2/3 ans I simpify

it :)

Step-by-step explanation: (-14, -1),(-5,5)

y2-y1

x2-x1

5-(-1)     = 6/3=2

-5-(-14)  = 9  /3 =3

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What is the slope of the line that contains the point ( -2, 7) and (2,3)​
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Find the polynomial of lowest degree with only real coefficients and having the given zeros. -7i and square root of 2
mario62 [17]

Answer:

x³ - (√2)x² + 49x - 49√2

Step-by-step explanation:

If one root is -7i, another root must be 7i.  You can't just have one root with i.  The other roos is √2, so there are 3 roots.  

x = -7i       is one root,

   (x + 7i) = 0    is the factor

x = 7i       is one root

  (x - 7i) = 0     is the factor

x = √2      is one root

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So the factors are...

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Multiply these out to find the polynomial...

(x + 7i)(x - 7i) =  x² + 7i - 7i - 49i²

Which simplifies to

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Now we have...

(x² + 49)(x - √2) = 0

Now foil this out...

 x²(x) - x²(-√2) + 49(x) + 49(-√2) = 0

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3 years ago
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I need help on this question
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i think A is the answer and why cant you just click the little ask for help button?

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Read 2 more answers
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