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Valentin [98]
3 years ago
10

Find the slope of (-14, -1),(-5,5)

Mathematics
1 answer:
avanturin [10]3 years ago
5 0

Answer: The slope is 2/3 ans I simpify

it :)

Step-by-step explanation: (-14, -1),(-5,5)

y2-y1

x2-x1

5-(-1)     = 6/3=2

-5-(-14)  = 9  /3 =3

You might be interested in
Write a formula for quadratic function if its graph has the vertex at point (0,6) and passes through the point (−1,−2).
d1i1m1o1n [39]

Answer:

y = - 8x² + 6

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k) = (0, 6), thus

y = a(x - 0)² + 6, that is

y = ax² + 6

To find a substitute (- 1, - 2) into the equation

- 2 = a(- 1)² + 6, that is

- 2 = a + 6 ( subtract 6 from both sides )

- 8 = a

y = - 8x² + 6

4 0
3 years ago
Look at the graph of connected points in the plane which make up a function,
mihalych1998 [28]

Answer:

-2 ≤ f(x) ≤ 4

Step-by-step explanation:

The range is the set or group of all the y-coordinates of the function. This means it has all the values from the bottom point at -2 to the top point at 4. It is written as an inequality.

-2 ≤ f(x) ≤ 4

7 0
3 years ago
Which equation is the inverse of y = 2x^2 - 8?
evablogger [386]

Answer: A

Step-by-step explanation:

y=2x^2-8

1. Swap x and y.

x=2y^2-8

2. Solve for the new y.

Add 8

x+8=2y^2

Divide by 2.

\frac{x+8}{2}=y^2

Extract the square root.

\sqrt{\frac{x+8}{2} }=y

6 0
4 years ago
What is the missing constant term in the perfect square that starts with x^2-20xx 2 −20xx, squared, minus, 20, x ?
tangare [24]

Answer:

Missing constant: 100

Step-by-step explanation:

perfect square  (a - b)^2 = a^2 - 2ab + b^2

In this case

20x = 2 * x * 10

and

10^2 = 100

so

(x - 10)^2 = x^2 - 20x + 100

8 0
3 years ago
3(18-7)+2<br><br> evaluate each expression using the order of operations
aksik [14]

Answer:

it is 35

Step-by-step explanation:

4 0
3 years ago
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