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jarptica [38.1K]
2 years ago
12

Alexandra deposited $1,000 in

Mathematics
1 answer:
allochka39001 [22]2 years ago
4 0

~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\\ P=\textit{original amount deposited}\dotfill & \$1000\\ r=rate\to 3.5\%\to \frac{3.5}{100}\dotfill &0.035\\ t=years\dotfill &5 \end{cases} \\\\\\ I = (1000)(0.035)(5)\implies I=175

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Need some help with these problems please.
goldenfox [79]

Answer:

See below.

Step-by-step explanation:

a.  

Divide the leading terms:

6x^4 / 2x^2 = 3x^2

3x2 is a parabola so the long run is

as x ---> +/- infinity r(x) ----> + infinity. (answer).

b.

10,000x^3 / 50 x^3

= 200.

So r(x) as a horizontal asymptote at y ( r(x)) = 200.  (answer).

3 0
3 years ago
What is the answer to 7 inches more than normal
dsp73
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7 0
3 years ago
Step 3: Apply Quantitative Tools
Sonja [21]

Answer: Total old car is $2955.89, new car $1080.94 *for 3yrs

Step-by-step explanation:

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I keep the old car # 1

8 0
2 years ago
Given the function f(x) = 3|x – 2| + 6, for what values of x is f(x) = 18?
Nikolay [14]

Answer:

x = -2, x = 6

Step-by-step explanation:

18 = 3|x - 2| + 6

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4 = |x - 2|

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4 0
2 years ago
Read 2 more answers
Find 2 sum whose sum is 4806 and difference is 1050 explanation​
arlik [135]

Answer:

The two numbers are 2928 and 1878

Step-by-step explanation:

Given this information, we can set up two equations:

x + y = 4806

x - y = 1050

We can solve these simultaneous equations by elimination, which means we can either add or subtract the two equations to solve one of the variables.

In this case, adding the equations together will eliminate y so we can solve for x (remember that y + - y is the same as y - y):

   x + y = 4806

+  x - y = 1050

____________

   2x     = 5856

This can then be simplified to x = 2928 (by dividing by 2)

Now we know x, we can substitute this value into any equation to find y:

2928 + y = 4806 so y = 4806 - 2928 which is 1878.

The two numbers are 2928 and 1878.

Hope this helps!

7 0
2 years ago
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