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2 years ago

7

A new club sent out 180 coupons to boost sales for next year's memberships. They provided 4 times as many to potential members t

han to existing members. How many coupons did they send to existing members?

1 answer:

pashok25 [27]2 years ago

3 0

They sent 36 coupons to the existing members

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You take a random token from a bag that contains 44? red, 1414? green, and 66? blue tokens. What is the probability your token i

german

Answer:

11/381

Step-by-step explanation:

Not sure what the ? after each number means but I'm going to assume they aren't there

so we need find the number of tokens in all which is

44+1414+66=1524

P(red)=44/1524 now reduce giving P(red)=11/381

5 0

3 years ago

Read 2 more answers

15 inches of snow fell in 12 hours. At this rate, how many inches of snow will fall in 3 days.

kirill [66]

Answer:

90 in

Step-by-step explanation:

15 x 6 = 90 in

This is because

6 x 12 hrs = 3 days

8 0

3 years ago

Read 2 more answers

Please help! If i don't get all my homework done I can't leave the house, but I'm stuck on this question.

TEA [102]

Plug y=-4x+5 into a website called desmos, it will give you a graph! The y-intercept is 5 and it’s at a slope of 4/1

7 0

3 years ago

2x1= how much answer

Vilka [71]

It’s two

Explanation:
2x1 = 2

5 0

3 years ago

What is the quadratic regression equation for the data set? <br><br> PLEASEE HELP ME

Soloha48 [4]

You're trying to find constants $a_0,a_1,a_2$ such that $\hat y=a_0+a_1\hat x+a_2{\hat x}^2$ . Equivalently, you're looking for the least-square solution to the following matrix equation.

$\underbrace{\begin{bmatrix}1&6&6^2\\1&3&3^2\\\vdots&\vdots&\vdots\\1&9&9^2\end{bmatrix}}_{\mathbf A}\underbrace{\begin{bmatrix}a_0\\a_1\\a_2\end{bmatrix}}_{\mathbf x}=\underbrace{\begin{bmatrix}100\\110\\\vdots\\70\end{bmatrix}}_{\mathbf b}$

To solve $\mathbf{Ax}=\mathbf b$ , multiply both sides by the transpose of $\mathbf A$ , which introduces an invertible square matrix on the LHS.

$\mathbf{Ax}=\mathbf b\implies\mathbf A^\top\mathbf{Ax}=\mathbf A^\top\mathbf b\implies\mathbf x=(\mathbf A^\top\mathbf A)^{-1}\mathbf A^\top\mathbf b$

Computing this, you'd find that

$\mathbf x=\begin{bmatrix}a_0\\a_1\\a_2\end{bmatrix}\approx\begin{bmatrix}121.119\\-3.786\\-0.175\end{bmatrix}$

which means the first choice is correct.

8 0

3 years ago