Answer:
Step-by-step explanation:
I know that there is a zero and a 1 involved in this somewhere. The only answer I can get which is a bit of a cheat, is
1^0! = 0!^1
These are not exactly the same thing. The trouble is that they are equal. There is a difference between "not the same thing" and "equal."
If I think of something else, I'll put it in a comment.
Answer:
The average value of 
over the interval ![[-2,5]](https://tex.z-dn.net/?f=%5B-2%2C5%5D)
is 
.
Step-by-step explanation:
Let suppose that function is continuous and integrable in the given intervals, by integral definition of average we have that:
(1)
(2)
By Fundamental Theorems of Calculus we expand both expressions:
(1b)
(2b)
We obtain the average value of over the interval ![[-2, 5]](https://tex.z-dn.net/?f=%5B-2%2C%205%5D)
by algebraic handling:
![F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)](https://tex.z-dn.net/?f=F%285%29%20-%20F%283%29%20%2B%5BF%283%29-F%28-2%29%5D%20%3D%2040%20%2B%20%28-30%29)
The average value of over the interval is .
Answer:
-0.5 and 5.5
Step-by-step explanation:
removing absolute value will yield two equation: 2.5-y=3 and 2.5-y=-3
solve for y in both case.
Answer:
x=-1
Step-by-step explanation:
2x+3/4(4x+16)=7
2x+(3x12)=7--->distributive property
2x+3x+12=7
5x+12=7--->addition property
5x=-5--->subtraction peroperty
x= -1---?division property
