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xenn [34]
3 years ago
15

x and x+1 are the two continuous natural numbers, then (i) Write the next two natural numbers. (ii) Find the product of first an

d the fourth number. (iii) Find the product of second and the third number. (iv) Find the relation between these products.
Mathematics
2 answers:
Gala2k [10]3 years ago
7 0

Answer:

(i)  X+2 and x+3;

(ii) x( x+4)= X^2 +4x;

(iii) x( x+4)=a

    (x+1)(x+3)= a+3  

Step-by-step explanation:

(i)  X+2 and x+3;

(ii) x( x+4)= X^2 +4x;

(iii) (x+1)(x+3)=x^2+3X+X+3=x^2+4x+3;

x(x+4)=a

(x+1)(x+3)= a+3

Alinara [238K]3 years ago
3 0

Step-by-step explanation:

x is followed by x+1 so each time we add one

our sequence goes like this:

  • x
  • x+1
  • x+1+1⇒ x+2
  • x+2+1⇒x+3

the first number is x and the fourth one is x+3

  • x*(x+3)
  • x²+3x

the second number is x+1 and the third one is x+2

  • (x+1)(x+2)
  • x²+2x+x+2
  • x²+3x+2

the first product is x²+3x and the second one is x²+3x+2

Let P be x²+3x and P' be x²+3x+2

  • P'-P = 2
  • P' = P+2
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\frac{56.78*5}{3} \\\frac{283.9}{3} \\94.6333333333333...

Your regular price sounds recurring, so you might have made a mistake copying.

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3 years ago
Regular price : $90, discount percent : 40%
Alex17521 [72]
90 x 0.4 = 36

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Mr. Wells runs a telecommunications company. While going through the company's project records, he found that there were 8 engin
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There are 12 project managers that are employed by Mr. Wells

<h3>Further explanation</h3>

Solving linear equation mean calculating the unknown variable from the equation.

Let the linear equation : y = mx + c

If we draw the above equation on Cartesian Coordinates , it will be a straight line with :

<em>m → gradient of the line</em>

<em>( 0 , c ) → y - intercept</em>

Gradient of the line could also be calculated from two arbitrary points on line ( x₁ , y₁ ) and ( x₂ , y₂ ) with the formula :

\large {\boxed{m = \frac{y_2 - y_1}{x_2 - x_1}}}

If point ( x₁ , y₁ ) is on the line with gradient m , the equation of the line will be :

\large {\boxed{y - y_1 = m ( x - x_1 )}}

<em>Let us tackle the problem!</em>

\texttt{ }

This problem is about Directly Proportional.

<em>There were 8 engineers under every team leader.</em>

\texttt{1 Team Leader} \rightarrow \texttt{8 engineers}

\texttt{15 Team Leader} \rightarrow 15 \times \texttt{8 engineers} = \boxed{\texttt{120 engineers}}

\texttt{ }

<em>There were 5 project managers for every 50 engineers.</em>

\texttt{50 engineers} \rightarrow \texttt{5 project managers}

\texttt{120 engineers} \rightarrow (120 \div 50) \times \texttt{5 project managers} = \boxed{\texttt{12 project managers}}

\texttt{ }

<h3>Learn more</h3>
  • Infinite Number of Solutions : brainly.com/question/5450548
  • System of Equations : brainly.com/question/1995493
  • System of Linear equations : brainly.com/question/3291576

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Linear Equations

Keywords: Linear , Equations , 1 , Variable , Line , Gradient , Point

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