Answer:
C. When there is no gas in the tank, 0 miles can be driven.
The larger one is (-11 + 41)/2 = 15.
The smaller one is (-11 -41)/2 = -26.
_____
For two numbers a and b with sum s and difference d, you can write the equations

Then adding the equations and dividing that sum by 2, you get

You can subtract the second eqution from the first and get a similar result for the smaller number

These are the formulas we used above.
The answer is A because if X represents the # of packages sold on Monday, then Tuesday can be represented by x+4 and Wednesday by x+6. Add the three expressions to get 3x+10=28, subtract 10 from both sides. 3x=28, divide by 3 and get x=6
Answer: 12
Step-by-step explanation:
Answer:
Step-by-step explanation:
Hello!
a.
Given the data corresponding the variables:
x 2 6 6 7 9
y 3 2 6 9 5
The Scatterplot is attached.
b.
To compute the correlation coefficient you need several auxiliary calculations:
∑X= 30
∑X²= 206
∑Y= 25
∑Y²= 155
∑XY= 162
![r= \frac{sumXY-\frac{(sumX)(sumY)}{n} }{\sqrt{[sumX^2-\frac{(sumX)^2}{n} ][sumY^2-\frac{(sumY)^2}{n} ]} }](https://tex.z-dn.net/?f=r%3D%20%5Cfrac%7BsumXY-%5Cfrac%7B%28sumX%29%28sumY%29%7D%7Bn%7D%20%7D%7B%5Csqrt%7B%5BsumX%5E2-%5Cfrac%7B%28sumX%29%5E2%7D%7Bn%7D%20%5D%5BsumY%5E2-%5Cfrac%7B%28sumY%29%5E2%7D%7Bn%7D%20%5D%7D%20%7D)
![r= \frac{162-\frac{(30)*(25)}{5} }{\sqrt{[206-\frac{(30)^2}{5} ][155-\frac{(25)^2}{5} ]} }](https://tex.z-dn.net/?f=r%3D%20%5Cfrac%7B162-%5Cfrac%7B%2830%29%2A%2825%29%7D%7B5%7D%20%7D%7B%5Csqrt%7B%5B206-%5Cfrac%7B%2830%29%5E2%7D%7B5%7D%20%5D%5B155-%5Cfrac%7B%2825%29%5E2%7D%7B5%7D%20%5D%7D%20%7D)
r= 0.429 ≅ 0.43
c.
The critical value for r has n-2 degrees of freedom, let's say for example you have α:0.05

For a two-tailed test.
Because the correlation coefficient is <u>positive</u> and the absolute value of the correlation coefficient, _<u>0.43</u>___, is <u>not greater</u> than the critical value for this data set,_<u>0.878</u>__, <u>no </u>linear relationship exists between x and y.
I hope it helps!