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slega [8]
2 years ago
6

Could someone help, I need help with math, this is the question. The ratio of ducks to geese is 5:3. There are 50 ducks. How man

y geese are there?
Mathematics
1 answer:
stepan [7]2 years ago
7 0
ANSWER:
There are 30 geese.
STEP-BY-STEP EXPLANATION:
Let y be the total no. of animals
Share= ratio/total ratio X total
50= 5/8 X y
50= 5y/8
50 X 8= 5y
y= 400/5
y= 80
The total no. of animals is 80
80-50=30 ans.
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Olenka [21]
To solve this we are going to use the half life equation N(t)=N_{0} e^{( \frac{-0.693t}{t _{1/2} }) }
Where:
N_{0} is the initial sample
t is the time in years
t_{1/2} is the half life of the substance
N(t) is the remainder quantity after t years 

From the problem we know that:
N_{0} =100
t=200
t_{1/2} =1600

Lets replace those values in our equation to find N(t):
N(200) =100e^{( \frac{(-0.693)(200)}{1600}) }
N(200)=100e^{( \frac{-138.6}{1600} )}
N(200)=100e^{-0.086625}
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8 0
3 years ago
2x + 2y = -2<br> 3x - 2y = 12<br> Solve By Elimination<br> Pls give me the hole equation
Sholpan [36]

Answer:

x = 2

y = -3

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2x + 2y = -2, then 2y = -2 - 2x

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-2 - 2x = 3x - 12

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divide both sides by 2:

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8 0
3 years ago
Part 2 of my first question.
azamat

Answer:

Step-by-step explanation:

integer=8

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5 0
3 years ago
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frez [133]
Factor using the difference of squares.

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4 0
3 years ago
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faust18 [17]

Answer:

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Step-by-step explanation:


8 0
3 years ago
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