Answer:
599 general admission tickets were sold while 277 reserved seats admission tickets were sold
Step-by-step explanation:
Here, we want to know the number of each types of tickets sold.
Let the number of general admission ticket be x while the number of reserved seats ticket be y
Mathematically since the total of both tickets is 876;
then;
x + y = 876 ••••••••••••(i)
The total amount of money generated from general admission is cost of general admission ticket * the number of general admission tickets sold = $2.50 * x = $2.50x
The total amount of money generated from reserved seat admission tickets sales is cost of reserved seat admission ticket * the number of reserved seats admission ticket sold = $5 * y = $5y
Adding both gives $2882.50
Thus;
2.5x + 5y = 2882.5 •••••••••(ii)
Now, from i, let’s say x = 876 -y
Let’s insert this into ii
2.5(876-y) + 5y = 2882.5
2190 -2.5y + 5y = 2882.5
2190 + 2.5y = 2882.5
2.5y = 2882.5 - 2190
2.5y = 692.5
y = 692.5/2.5
y = 277
Recall;
x = 876 -y
Thus;
x = 876 - 277 = 599
Answer:
I think x = -8. Hope this helps!! :)
Answer:
6/20 can I get brainliest pleast
Step-by-step explanation:
there is a chance that the teacher will pick a student without brown eyes 6/20 times
Answer:
30 sides
Step-by-step explanation:
Answer:
{0.16807, 0.36015, 0.3087, 0.1323, 0.02835, 0.00243}
Step-by-step explanation:
The expansion of (p+q)^n for n = 5 is ...
(p+q)^5 = p^5 +5·p^4·q +10·p^3·q^2 +10·p^2·q^3 +5·p·q^4 +q^5
When the probability p=0.3 and q = 1-p = 0.7 the terms of this series correspond to the probabilities of 5, 4, 3, 2, 1, and 0 favorable outcomes out of 5 trials.
For example, p^5 = 0.3^5 = 0.00243 is the probability of 5 favorable outcomes in 5 trials where the probability of each favorable outcome is 0.3.
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The attachment shows the calculation of these numbers using a graphing calculator. It lists them in reverse order of the expansion of (p+q)^5 shown above, so that they are the probabilities of 0–5 favorable outcomes in the order 0–5.
