Exactly 989527/1048576, or approximately 94.37%
Since each trait is carried on a different chromosome, the two traits are independent of each other. Since both parents are heterozygous for the trait, each parent can contribute 1 of a possible 4 combinations of the alleles. So there are 16 possible offspring. I'll use "a", "A", "b", "B" to represent each allele and the possible children are aabb, aabB, aaBb, aaBB, aAbb, aAbB, aABb, aABB, Aabb, AabB, AaBb, AaBB, AAbb, AAbB, AABb, and AABB
Of the above 16 possibilities, there are 7 that are homozygous in an undesired traint and 9 that don't exhibit the undesired trait. So let's first calculate the probability of "what are the chances that all 5 children not exhibiting an undesired trait?" and then subtract that result from 1. So
1-(9/16)^5 = 1 - 59049/1048576 = 989527/1048576 which is approximately 0.943686485 = 94.3686485%
So the answer is exactly 989527/1048576, or approximately 94.37%
Hey there!
<span>The near extinction of many bird species was caused by:
Answer: </span>
<span> use of DDT
Hope this helps
Have a great day (:
</span>
Is there a picture with this question? It seems like there's background information which isn't being shown here.
Pedigrees are basically a map of alleles for family trees
______Person1 -- Person2_____
I I I I
__Person3_ Person 4 Person5 _Person6___
I I I I I
Person7 Person8 Person9 Person10 Person11
And under everyone's name you write their alleles.
Punnett squares give the probability of someone having genes based on their parents' genes.
Parent1 (Aa) or Parent1 (aa)
Parent2 (AA) AA Aa Parent2 (Aa) Aa aa
AA Aa aa aa
