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3 years ago

9

Young Sally went Trick or Treating last Halloween, In her treat bag were 15 pieces of gum, 7 lollipops, 8 tootsie rolls, 6 candy

bars, and an apple.
a) Candy bars are her favorite. What percent of her treats are candy bars?
b) She really does not like gum or apples, What percent of the treats things she does not like?

1 answer:

Vilka [71]3 years ago

4 0

Answer:

A: 16.2% (if you need it rounded, it is 16%)

B: 43.2% (if you need it rounded it is 43%)

Step-by-step explanation:

We need to find the candy bar percentage rate so we divide the amount of candy bars, by the total about of treats collected.

15 + 7 + 8 + 6 + 1 = 37

Now we divide the cady bars by the total amount:

6/37 = 16.2%

Now we do the same thing again but this time with the apples and gum:

16/37 = 43.2%

You did it!

Have a great day!!

Please rate and mark brainliest!!

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4 years ago

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!!!!!HELP!!!!! 25 POINTS!!!

cluponka [151]

Answer:

Formula: A = 48,000(1+0.02)^t

salary after 30 years: $ 86,945.35

Step-by-step explanation:

Hi, to answer this question we have to apply an exponential growth function:

A = P (1 + r) t

Where:

p = initial salary

r = raising rate (decimal form)

t= years

A = salary after t years

Replacing with the values given:

A = 48,000 (1+ 2/100)^t

A = 48,000(1+0.02)^t

Salary after 30 years: substitute t=30

A = 48,000(1+0.02)^30

A = 48,000(1.02)^30

A=$ 86,945.35

Feel free to ask for more if needed or if you did not understand something.

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4 years ago

Read 2 more answers

A. Do some research and find a city that has experienced population growth.

horrorfan [7]

A. The city we will use is Orlando, Florida, and we are going to examine its population growth from 2000 to 2010. According to the census the population of Orlando was 192,157 in 2000 and 238,300 in 2010. To examine this population growth period, we will use the standard population growth equation $N_{t} =N _{0}e^{rt}$
where:
$N(t)$ is the population after $t$ years
$N_{0}$ is the initial population
$t$ is the time in years
$r$ is the growth rate in decimal form
$e$ is the Euler's constant
We now for our investigation that $N(t)=238300$ , $N_{0} =192157$ , and $t=10$ ; lets replace those values in our equation to find $r$ :
$238300=192157e^{10r}$
$e^{10r} = \frac{238300}{192157}$
$ln(e^{10r} )=ln( \frac{238300}{192157} )$
$r= \frac{ln( \frac{238300}{192157}) }{10}$
$r=0.022$
Now lets multiply $r$ by 100% to obtain our growth rate as a percentage:
$(0.022)(100)$ =2.2%
We just show that Orlando's population has been growing at a rate of 2.2% from 2000 to 2010. Its population increased from 192,157 to 238,300 in ten years.

B. Here we will examine the population decline of Detroit, Michigan over a period of ten years: 2000 to 2010.
Population in 2000: 951,307
Population in 2010: 713,777
We know from our investigation that $N(t)=713777$ , $N_{0} =951307$ , and $t=10$ . Just like before, lets replace those values into our equation to find $r$ :
$713777=951307e^{10r}$
$e^{10r} = \frac{713777}{951307}$
$ln(e^{10r} )=ln( \frac{713777}{951307} )$
$r= \frac{ln( \frac{713777}{951307}) }{10}$
$r=-0.029$
$(-0.029)(100)$ = -2.9%.
We just show that Detroit's population has been declining at a rate of 2.2% from 2000 to 2010. Its population increased from 192,157 to 238,300 in ten years.

C. Final equation from point A: $N(t)=192157e^{0.022t}$ .
Final equation from point B: $N(t)=951307e^{-0.029t}$
Similarities: Both have an initial population and use the same Euler's constant.
Differences: In the equation from point A the exponent is positive, which means that the function is growing; whereas, in equation from point B the exponent is negative, which means that the functions is decaying.

D. To find the year in which the population of Orlando will exceed the population of Detroit, we are going equate both equations $N(t)=192157e^{0.022t}$ and $N(t)=951307e^{-0.029t}$ and solve for t:
$192157e^{0.022t} =951307e^{-0.029t}$
$\frac{192157e^{0.022t} }{951307e^{-0.029t} } =1$
$e^{0.051t} = \frac{951307}{192157}$
$ln(e^{0.051t})=ln( \frac{951307}{192157})$
$t= \frac{ln( \frac{951307}{192157}) }{0.051}$
$t=31.36$
We can conclude that if Orlando's population keeps growing at the same rate and Detroit's keeps declining at the same rate, after 31.36 years in May of 2031 Orlando's population will surpass Detroit's population.

E. Since we know that the population of Detroit as 2000 is 951307, twice that population will be $2(951307)=1902614$ . Now we can rewrite our equation as: $N(t)=1902614e^{-0.029t}$ . The last thing we need to do is equate our Orlando's population growth equation with this new one and solve for t:
$192157e^{0.022t} =1902614e^{-0.029t}$
$\frac{192157e^{0.022t} }{1902614e^{-0.029t} } =1$
$e^{0.051t} = \frac{1902614}{192157}$
$ln(e^{0.051t} )=ln( \frac{1902614}{192157} )$
$t= \frac{ln( \frac{1902614}{192157}) }{0.051}$
$t=44.95$
We can conclude that after 45 years in 2045 the population of Orlando will exceed twice the population of Detroit.

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4 years ago

HELP P L E A S E ! !

alex41 [277]

Answer:

A is true but I dont know the rest I am very sorry .-.

Step-by-step explanation:

I Just added 18 + 12 = 30 + 10 = 40 and that is why A is true

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Is it possible to create two triangles with congruent side lengths but different angle measurements?

kotykmax [81]

Yes. If the side lengths are different, you can end up with different angle measurements (example: SSA~ property. You can have two sides that are the same but you can make two different triangles with those side lengths and that one angle.)

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