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Dmitry_Shevchenko [17]
2 years ago
14

Write down an inequality to describe each of these solution sets.

Mathematics
1 answer:
Ber [7]2 years ago
6 0

Answer:

(a) x<=2

(b) x>-2

(c) x>=10

(d) x<-20

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Please help! this is due tmr show work too please of can!
yKpoI14uk [10]
The rate of change is -5/4



I find it best to use the Slope formula
M= y2-y1/x2-x1



So we to use need any 2 points on the graph (I used the first 2)
•(0,200) and (80,100)

Now we set up the problem 100-200/80-0
Then you’ll subtract and should get
-100/80
Now you’ll simplify and once you’re done simplifying your answer should be -5/4.


Here is my work. Hope this Helps!

4 0
2 years ago
Help please need it for today
tensa zangetsu [6.8K]
Make a proportion of the diameter over the circumference.
185 feet / 580 feet = x / 10 feet
580x=1850
x= about 3.2

Diameter= about 3.2 feet

Hope this helps :)
4 0
3 years ago
Determine weather it is no solution many solutions or one solutions <br> 3(6-4m)=2(9-6m)
Vinil7 [7]

Answer:

Many solutions

Step-by-step explanation:

7 0
3 years ago
The two lines graphed below are not parallel. How many solutions are there to
Galina-37 [17]

Answer:B

Step-by-step explanation:

simple, there is one point of intersection or where the lines meet

8 0
2 years ago
Read 2 more answers
URGENT! PLEASE HELP.
Harrizon [31]

The distance BC from Tower 2 to the plane will be 14,065.5 ft and the height of the plane from the ground will be 5,720.9 ft.

<h3>What is a right-angle triangle?</h3>

It is a type of triangle in which one angle is 90 degrees and it follows the Pythagoras theorem and we can use the trigonometry function.

A plane is located at C on the diagram.

There are two towers located at A and B.

The distance between the towers is 7600 feet and angles of elevation are given.

Then in the right-angle triangle ΔADC, we have

\rm \tan 16 = \dfrac{H}{7600 + X}\\\\\\H = 0.2867(7600 +X)\\\\\\H = 0.2756\ X + 2179.2649 ...1

Then in the right-angle triangle ΔBDC, we have

\rm \tan24 = \dfrac{H}{ X}\\\\\\H = 0.4452\ X ...2

From equations 1 and 2, we have

0.4452X = 0.2756 X + 2179.2649

0.1696X = 2179.2649

            X = 12849.439 ≅ 12,849.4 ft

Then the distance BC from Tower 2 to the plane will be

\rm BC = \dfrac{12849.4}{\cos 24}\\\\\\BC = 14065.5 \ ft

Then the height of the plane from the ground will be

\rm H = 12849.4 \times  \tan 24 \\\\\\H = 5720.9 \ ft

The figure is shown below.

More about the right-angle triangle link is given below.

brainly.com/question/3770177

#SPJ1

3 0
2 years ago
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