All categories

3 years ago

What comes next in this pattern? 7/2, 6/3, 5/4, ... 4/9 4/7 4/5

Mathematics

1 answer:

dolphi86 [110]3 years ago

4 0

Answer:

I'm guessing 3/2

Step-by-step explanation:

I can see the pattern that it's doing down, up and then down again

7/2 to 6/3

5/4 to 4/9 and so on

You might be interested in

After 14 boys leave a concert, the ratio of boys to girls is 3:10. If there are p girls at the concert, write an algebraic expre

Gemiola [76]

I think there was 17 boys at the beginning of the concert. But i don't know how to put it in terms of P

3 0

3 years ago

Mrs. Anders gave her class 15 minutes to read. Courtney read 8 ½ pages in that time. At what rate, in pages per hour, would Cour

arlik [135]

Answer:

Step-by-step explanation:

15 mins is 1/4 od an hour so mulitply 8 1/2 (8.5) x 4

4 0

3 years ago

Read 2 more answers

What are the coordinates of the imageof point A (2, -7) under the transalition (x,y) (x- 3, y 5)

jenyasd209 [6]

Answer:

The coordinates of the image of point A (2, -7) are A'(-1,-2).

Step-by-step explanation:

Note: The sign is missing between y and 5 in the rule of transitional.

Consider the rule of translation is

$(x,y)\Rightarrow (x-3,y+5)$

We need to find the image of point A (2, -7).

Substitute x=2 and y=-7 in the above rule.

$A(2,-7)\Rightarrow A'(2-3,-7+5)$

$A(2,-7)\Rightarrow A'(-1,-2)$

Therefore, the coordinates of the image of point A (2, -7) are A'(-1,-2).

4 0

3 years ago

A washer and a dryer cost $790 combined. The washer costs $40 more than the dryer. What is the cost of the dryer?

Pepsi [2]

if the washer and dryer cost $790 then you would divide 790 by 2.

then you will get $395

then you add 40 to $395 and will get $435

so the answer is $435

7 0

3 years ago

(10 points) Consider the initial value problem y′+3y=9t,y(0)=7. Take the Laplace transform of both sides of the given differenti

Rashid [163]

Answer:

The solution

$Y (s) = 9( -1 +3 t + e^{-3 t} ) + 7 e ^{-3 t}$

Step-by-step explanation:

Explanation:-

Consider the initial value problem y′+3 y=9 t,y(0)=7

Step(i):-

Given differential problem

y′+3 y=9 t

Take the Laplace transform of both sides of the differential equation

L( y′+3 y) = L(9 t)

Using Formula Transform of derivatives

L(y¹(t)) = s y⁻(s)-y(0)

By using Laplace transform formula

$L(t) = \frac{1}{S^{2} }$

Step(ii):-

Given

L( y′(t)) + 3 L (y(t)) = 9 L( t)

$s y^{-} (s) - y(0) + 3y^{-}(s) = \frac{9}{s^{2} }$

$s y^{-} (s) - 7 + 3y^{-}(s) = \frac{9}{s^{2} }$

Taking common y⁻(s) and simplification, we get

$( s + 3)y^{-}(s) = \frac{9}{s^{2} }+7$

$y^{-}(s) = \frac{9}{s^{2} (s+3}+\frac{7}{s+3}$

Step(iii):-

By using partial fractions , we get

$\frac{9}{s^{2} (s+3} = \frac{A}{s} + \frac{B}{s^{2} } + \frac{C}{s+3}$

$\frac{9}{s^{2} (s+3} = \frac{As(s+3)+B(s+3)+Cs^{2} }{s^{2} (s+3)}$

On simplification we get

9 = A s(s+3) +B(s+3) +C(s²) ...(i)

Put s =0 in equation(i)

9 = B(0+3)

B = 9/3 = 3

Put s = -3 in equation(i)

9 = C(-3)²

C = 1

Given Equation 9 = A s(s+3) +B(s+3) +C(s²) ...(i)

Comparing 'S²' coefficient on both sides, we get

9 = A s²+3 A s +B(s)+3 B +C(s²)

0 = A + C

put C=1 , becomes A = -1

$\frac{9}{s^{2} (s+3} = \frac{-1}{s} + \frac{3}{s^{2} } + \frac{1}{s+3}$

Step(iv):-

$y^{-}(s) = \frac{9}{s^{2} (s+3}+\frac{7}{s+3}$

$y^{-}(s) =9( \frac{-1}{s} + \frac{3}{s^{2} } + \frac{1}{s+3}) + \frac{7}{s+3}$

Applying inverse Laplace transform on both sides

$L^{-1} (y^{-}(s) ) =L^{-1} (9( \frac{-1}{s}) + L^{-1} (\frac{3}{s^{2} }) + L^{-1} (\frac{1}{s+3}) )+ L^{-1} (\frac{7}{s+3})$

By using inverse Laplace transform

$L^{-1} (\frac{1}{s} ) =1$

$L^{-1} (\frac{1}{s^{2} } ) = \frac{t}{1!}$

$L^{-1} (\frac{1}{s+a} ) =e^{-at}$

Final answer:-

Now the solution , we get

$Y (s) = 9( -1 +3 t + e^{-3 t} ) + 7 e ^{-3t}$

5 0

3 years ago