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2 years ago

Hello people ~what's the product of the square root of 3 and the square root of 12

Mathematics

2 answers:

Elis [28]2 years ago

7 0

Let's see

$\\ \rm\rightarrowtail \sqrt{3}\times \sqrt{12}$

$\\ \rm\rightarrowtail \sqrt{3}\times \sqrt{2(2)(3)}$

$\\ \rm\rightarrowtail \sqrt{3}\times 2\sqrt{3}$

$\\ \rm\rightarrowtail 2(3)$

$\\ \rm\rightarrowtail 6$

MArishka [77]2 years ago

4 0

Answer:

Step-by-step explanation:

sqrt(3) x sqrt(12) = sqrt(3) x sqrt(4x3) = sqrt(3) x 2sqrt(3)

= 2 ( sqrt(3)² ) = 2 x 3 = 6

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Add 3/4+(−2 1/2) using the number line.

Neko [114]

Answer:

-1 3/4

Step-by-step explanation:

6 0

4 years ago

How do you Solve d+7/−3=4?

vova2212 [387]

Answer:

One solution was found :

d = 19/3 = 6.333

Step-by-step explanation:

Step by step solution :

Step 1 :

Simplify ——

-3

Equation at the end of step 1 :

(d + ——) - 4 = 0

-3

Step 2 :

Rewriting the whole as an Equivalent Fraction :

2.1 Adding a fraction to a whole

Rewrite the whole as a fraction using -3 as the denominator :

d d • -3

d = — = ——————

1 -3

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

2.2 Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

d • 3 + 7 • -1 3d - 7

—————————————— = ——————

3 3

Equation at the end of step 2 :

(3d - 7)

———————— - 4 = 0

Step 3 :

Rewriting the whole as an Equivalent Fraction :

3.1 Subtracting a whole from a fraction

Rewrite the whole as a fraction using 3 as the denominator :

4 4 • 3

4 = — = —————

1 3

Adding fractions that have a common denominator :

3.2 Adding up the two equivalent fractions

(3d-7) - (4 • 3) 3d - 19

———————————————— = ———————

3 3

Equation at the end of step 3 :

3d - 19

——————— = 0

Step 4 :

When a fraction equals zero :

4.1 When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

3d-19

————— • 3 = 0 • 3

Now, on the left hand side, the 3 cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

3d-19 = 0

Solving a Single Variable Equation :

4.2 Solve : 3d-19 = 0

Add 19 to both sides of the equation :

3d = 19

Divide both sides of the equation by 3:

d = 19/3 = 6.333

One solution was found :

d = 19/3 = 6.333

6 0

3 years ago

John got 24 out of 25 total questions correct on his test. What percent did he score on his test?

mamaluj [8]

Answer:

24 out of 25 is equal to 96%

96% = A

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

The probability that a professor arrives on time is 0.8 and the probability that a student arrives on time is 0.6. Assuming thes

saul85 [17]

Answer:

a)0.08 , b)0.4 , C) i)0.84 , ii)0.56

Step-by-step explanation:

Given data

P(A) = professor arrives on time

P(A) = 0.8

P(B) = Student aarive on time

P(B) = 0.6

According to the question A & B are Independent

P(A∩B) = P(A) . P(B)

Therefore

${A}'$ & ${B}'$ is also independent

${A}'$ = 1-0.8 = 0.2

${B}'$ = 1-0.6 = 0.4

part a)

Probability of both student and the professor are late

P(A'∩B') = P(A') . P(B') (only for independent cases)

= 0.2 x 0.4

= 0.08

Part b)

The probability that the student is late given that the professor is on time

$P(\frac{B'}{A})$ = $\frac{P(B'\cap A)}{P(A)}$ = $\frac{0.4\times 0.8}{0.8}$ = 0.4

Part c)

Assume the events are not independent

Given Data

P $(\frac{{A}'}{{B}'})$ = 0.4

= $\frac{P({A}'\cap {B}')}{P({B}')}$ = 0.4

$P$ $({A}'\cap {B}')$ = 0.4 x P $({B}')$

= 0.4 x 0.4 = 0.16

$P({A}'\cap {B}')$ = 0.16

The probability that at least one of them is on time

$P(A\cup B)$ = 1- $P({A}'\cap {B}')$

= 1 - 0.16 = 0.84

ii)The probability that they are both on time

P $(A\cap B)$ = 1 - $P({A}'\cup {B}')$ = 1 - $[P({A}')+P({B}') - P({A}'\cap {B}')]$

= 1 - [0.2+0.4-0.16] = 1-0.44 = 0.56

6 0

3 years ago

What is 10*9*8*7*6*5*4*3*2*1?

nordsb [41]

Welcome to the factorial world :) Remember the Exclamation Point ( ! ) on the calculator, that is called factorial.
For instance: 1! = 1
2! = 1 x 2
3! = 1 x 2 x 3
and so on
10! = 1 x 2 x 3 x 4 x 5 x 6 x 7 x 8 x 9 x 10 = 3628800
Crazy enough, 0! is actually equal to 1, try that on your calculator XD

6 0

3 years ago

Hello people ~what's the product of the square root of 3 and the square root of 12​

Hello people ~what's the product of the square root of 3 and the square root of 12