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3 years ago

If the width of a rectangle with periemter is P is 6 units what is its length

Mathematics

1 answer:

Hoochie [10]3 years ago

3 0

Answer:

L = $\frac{P - 12}{2}$

Step-by-step explanation:

Since perimeter is 2L + 2W, and width is 6, then P = 2L + 2*6, and solving for L gives you (P - 12)/2

Hopefully this helps- let me know if you have any questions!

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How to solve -8+squre root (5a-5)=-3

sertanlavr [38]

Answer:

$a=6$

Step-by-step explanation:

Given equation:

$-8+\sqrt{5a-5}=-3$

Solving for unknown variable $a$

Adding 8 both sides by additive property of equality.

$+8-8+\sqrt{5a-5}=-3+8$

$\sqrt{5a-5}=5$

Squaring both sides to remove the square root.

$(\sqrt{5a-5})^2=5^2$

$5a-5=25$

Adding 5 both sides by additive property of equality.

$5a-5+5=25+5$

$5a=30$

Dividing both sides by 6 to isolate $a$

$\frac{5a}{5}=\frac{30}{5}$

∴ $a=6$

8 0

3 years ago

Please help me out solve it and tell me how you got that answer so I can understand please!

NikAS [45]

The solution for s in the given equation is $s = C-nD$

The question seems to be incomplete

Here is the complete question:

Solve for s in this equation $D= \frac{C-s}{n}$ Depreciation.

To solve for s, that means we should make s the subject of the equation

From the given equation,

$D= \frac{C-s}{n}$

To solve for s, first multiply both sides by n to clear the fraction

We get

$n\times D= n \times \frac{C-s}{n}$

Then,

$nD = C - s$

Now, add s to both sides

$nD + s= C - s+s$

$nD+s = C$

Then, subtract nD from both sides

$nD-nD+s = C-nD$

∴ $s = C-nD$

Hence, the solution for s in the given equation is $s = C-nD$

Learn more here: brainly.com/question/21406377

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3 years ago

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Answer:

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Step-by-step explanation:

10000000000000o0000000000000000000000000000000000000000ooooooooooooooooooooooooooo0000oooo00o0o0o0oo00oooooooo0000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000ooooooooooooooooooooooooooooooooooooooo

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