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3 years ago

If the width of a rectangle with periemter is P is 6 units what is its length

Mathematics

1 answer:

Hoochie [10]3 years ago

3 0

Answer:

L = $\frac{P - 12}{2}$

Step-by-step explanation:

Since perimeter is 2L + 2W, and width is 6, then P = 2L + 2*6, and solving for L gives you (P - 12)/2

Hopefully this helps- let me know if you have any questions!

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A skydiver's speed during a free fall

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Step-by-step explanation:

1. 165/3.3 = 50 meters/second.

2. In 4 seconds the skydiver will fall 4*50 = 200 meters.

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A barbeque restaurant serves four meats brisket chicken ribs and turkey how many two meat combo can be served for the luncheon p

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3 years ago

The owner of a produce stand is selling baskets of peaches, priced by the kilogram. She rounded each measurements to the nearest

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Answer:

$1\frac{1}{2}kg$

Step-by-step explanation:

Given

$a = 6\frac{1}{2}$ --- heaviest

$b = 5$ --- second heaviest

Required

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This is calculated as:

$d = 6\frac{1}{2} - 5$

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3 years ago

the base of a right triangle is (x-5). The height of the triangle is (2x+1). The perimeter of the triangle is (7x+5). Find the a

Dovator [93]

Answer:

Area: (x^2)-(9x/2)-2 3rd side=4x+9

Step-by-step explanation:

First, let's find the third side. If all of the sums add up to 7x+5, then we can easily subtract the two sides that we do have.

2x+1+x-5=3x-4

Now, you have to ask yourself what added to 3x-4 can be equal to 7x+5.

It's 4x+9 because we combine like terms. That's the third side. Now, we should follow the formula for getting the area of triangle using the side lengths:

(2x+1)(x-5)/2=area of triangle

2x*x=2x^2

2x*-5=-10x

x*1=x

-5*1=-5

Now the total is 2x^2-9x-4 when you continue to combine like terms. Now all we have to do is divide by 2. So, the area is 2x^2-9x-4/2. You can simplify that. Answer is up top.

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3 years ago

A projectile is fired at such an angle that the vertical

svetoff [14.1K]

(a) The projectile remains in the air for 10 seconds

(b) It travels a horizontal distance of 600 meters

Step-by-step explanation:

A projectile is fired at such an angle that

1. The vertical component of its velocity is 49 m/sec

2. The horizontal component of its velocity is 60 m/sec

We need to find:

(a) How long the projectile remains in the air

(b) The horizontal distance it travels

∵ The vertical distance y = $u_{y}$ t - $\frac{1}{2}$ g t², where

$u_{y}$ is the vertical component of its velocity, g is the acceleration

of gravity and t is the time

∵ y = 0 ⇒ it return to the same initial height

∵ $u_{y}$ = 49 m/s

∵ g = 9.8 m/s²

- Substitute these values in the rule above

∴ 0 = 49 t - $\frac{1}{2}$ (9.8) t²

∴ 0 = 49 t - 4.9 t²

- Take t as a common factor

∴ 0 = t (49 - 4.9 t)

- Equate each term by 0

∴ t = 0 ⇒ at initial position

∴ 49 - 4.9 t = 0

- Add 4.9 t to both side

∴ 49 = 4.9 t

- Divide both sides by 4.9

∴ t = 10 seconds

(a) The projectile remains in the air for 10 seconds

∵ The horizontal distance = $u_{x}$ t, where $u_{x}$ is the

horizontal component of its velocity

∵ $u_{x}$ = 60 m/sec

∵ t = 10 seconds

∴ x = 60 × 10 = 600 meters

(b) It travels a horizontal distance of 600 meters

Learn more:

You can learn more about the component of velocity in brainly.com/question/4464845

#LearnwithBrainly

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3 years ago