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qwelly [4]
4 years ago
15

If eight out of every thirteen trick-or-treaters that came to your house last Halloween were dressed as knights, what proportion

of trick-or-treaters were not dressed as knights?
Mathematics
1 answer:
yanalaym [24]4 years ago
3 0
5/13 kids weren't dressed as knights
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At a store, a hat has a regular price of x dollars. During a sale, the price of the hat is discounted by 20%. The expression 0.8
mihalych1998 [28]

Answer: D) x - 0.2x

Step-by-step explanation:

The hat has a regular price of x dollars.

This price is reduced by 20% so the relevant expression for the discount is; 20% * x or; 0.2x

The discounted price will be the price of the hat less the discount which means the formula will be;

= Price - discount

= x - 0.2x

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Area of part of a circles
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Answer:

56.55 or 18pi

Step-by-step explanation:

Pi time radius squared divided by two

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50 POINTS
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Step-by-step explanation:

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the table shows the shoe colour of 21 people a bar chart showing this information has been started a) fill in the lable for the
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Step-by-step explanation:

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3 years ago
Plot the point whose polar coordinates are given. Then find the Cartesian coordinates of the point. (a) (5, 3π/2) (x, y) = (b) (
Vlad1618 [11]

Answer:

A)(5,\frac{3\pi}{2})=(0,-5)\:B)(\frac{3}{2} , \frac{\pi}{4} ) \Rightarrow (\frac{3\sqrt{2}}{4} ,\frac{3\sqrt{2}}{4} )\:C)(-1,\frac{\pi}{6})= (\frac{\sqrt{3}}{2},\frac{1}{2})

Step-by-step explanation:

1) Check the Polar Coordinates on the graph.

2) A polar coordinate is given in (r,\theta) Let's transform each polar coordinate into Cartesian one. Considering:

A)

x=rcos\theta\\y=rsin\theta\\

A) (5,\frac{3\pi}{2})\\cos(\theta)=\frac{x}{5}\\cos(\frac{3\pi}{2})=\frac{x}{5}\:Cross\: Multiplying\\x=5 cos(\frac{3\pi}{2})\\x =5 cos(0)\:x=0\\sin(\frac{3\pi}{2})=\frac{y}{5}\\y=5sin(-1)\\y=-5\\(0,-5)

B) (b) (3/2 , π/4)

B) (\frac{3}{2},\frac{\pi}{4})\\cos(\theta)=\frac{x}{\frac{3}{2}}\\\frac{3}{2}cos(\frac{\pi}{4})=x\:Cross\: Multiplying\\x=\frac{3}{2}*\frac{\sqrt{2}}{2}\\x =\frac{3\sqrt{2}}{4} \approx 1.06

y=\frac{3}{2}sin(\frac{\pi}{4})\Rightarrow y =\frac{3\sqrt{2}}{4}

B)(\frac{3}{2} , \frac{\pi}{4} ) \Rightarrow (\frac{3\sqrt{2}}{4} ,\frac{3\sqrt{2}}{4} )

C) (c) (−1, −π/6)

C) (-1,-\frac{\pi}{6})\\cos(\theta)=\frac{x}{-1}\\-cos(\frac{-\pi}{6})=x\:Cross\: Multiplying\\x=\frac{\sqrt{3}}{2}

(-1,-\frac{\pi}{6})\\sin(\theta)=\frac{x}{-1}\\-sin(\frac{-\pi}{6})=x\:Cross\: Multiplying\\x=\frac{1}{2}

C)(-1,\frac{\pi}{6})= (\frac{\sqrt{3}}{2},\frac{1}{2})

6 0
3 years ago
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