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qwelly [4]
3 years ago
15

If eight out of every thirteen trick-or-treaters that came to your house last Halloween were dressed as knights, what proportion

of trick-or-treaters were not dressed as knights?
Mathematics
1 answer:
yanalaym [24]3 years ago
3 0
5/13 kids weren't dressed as knights
You might be interested in
A container built for transatlantic shipping is constructed in the shape of a right rectangular prism. Its dimensions are 7.5 ft
Yuri [45]

Considering the definition of right rectangular prism and its volume,  the total weight of the contents is 38.81 pounds.

<h3>Right rectangular prism</h3>

A right rectangular prism (or cuboid) is a polyhedron whose surface is formed by two equal and parallel rectangles called bases and by four lateral faces that are also parallel rectangles and equal two to two.

<h3>Volume of right rectangular prism</h3>

To calculate the volume of the rectangular prism, it is necessary to find the product of its dimensions, or of the three edges that converge at a certain vertex.

That is, to calculate the volume of a rectangular prism, multiply its 3 dimensions: length×width×height.

<h3>Volume of the container </h3>

In this case, you know that:

  • the dimensions of the container built are 7.5 ft by 11.5 ft by 3 ft.
  • the container is entirely full and, on average, its contents weigh 0.15 pounds per cubic foot.

So, the volume of the container is calculated as:

7.5 ft× 11.5 ft× 3 ft= <u><em>258.75 ft³</em></u>

Then, the total weight of the contents is calculated as:

258.75 ft³×  0.15 pounds per cubic foot= <u><em>38.8125 pounds≅ 38.81 pounds</em></u>

Finally, the total weight of the contents is 38.81 pounds.

Learn more with this similar problems:

<u>brainly.com/question/13962136</u>

<u>brainly.com/question/7171617</u>

8 0
2 years ago
Let f(x)=1/2x2+4. The function g(x) is a vertical stretch of f(x) by a factor of 4. What is the equation of g(x)?
andrey2020 [161]

The equation of g(x) is g(x)=2 x^{2}+16

Explanation:

Given that the function f(x) is f(x)=\frac{1}{2} x^{2}+4

Also, given that the function g(x) is a vertical stretch of f(x) by a factor of 4.

We need to determine the equation of g(x)

<u>Equation of g(x):</u>

The vertical stretch of the function can be determined by multiplying the factor 4 with the function f(x).

Thus, we have,

g(x)=4 f(x)

Substituting the values,we have,

g(x)=4\left(\frac{1}{2} x^{2}+4\right)

Simplifying the values, we get,

g(x)=2 x^{2}+16

Hence, the equation of g(x) is g(x)=2 x^{2}+16

6 0
3 years ago
Write an inequality to compare the absolute of -32 and the absolute value of -23.
AveGali [126]
The absolute value of -32 is greater than the absolute value of -23
6 0
3 years ago
A random sample of 500 registered voters in Phoenix is asked if they favor the use of oxygenated fuels year-round to reduce air
Stells [14]

Answer:

a) 0.0853

b) 0.0000

Step-by-step explanation:

Parameters given stated that;

H₀ : <em>p = </em>0.6

H₁ : <em>p  = </em>0.6, this explains the acceptance region as;

p° ≤ \frac{315}{500}=0.63 and the region region as p°>0.63 (where p° is known as the sample proportion)

a).

the probability of type I error if exactly 60% is calculated as :

∝ = P (Reject H₀ | H₀ is true)

   = P (p°>0.63 | p=0.6)

where p° is represented as <em>pI</em><em> </em>in the subsequent calculated steps below

   

    = P  [\frac{p°-p}{\sqrt{\frac{p(1-p)}{n}}} >\frac{0.63-p}{\sqrt{\frac{p(1-p)}{n}}} |p=0.6]

    = P  [\frac{p°-0.6}{\sqrt{\frac{0.6(1-0.6)}{500}}} >\frac{0.63-0.6}{\sqrt{\frac{0.6(1-0.6)}{500}}} ]

    = P   [Z>\frac{0.63-0.6}{\sqrt{\frac{0.6(1-0.6)}{500} } } ]

    = P   [Z > 1.37]

    = 1 - P   [Z ≤ 1.37]

    = 1 - Ф (1.37)

    = 1 - 0.914657 ( from Cumulative Standard Normal Distribution Table)

    ≅ 0.0853

b)

The probability of Type II error β is stated as:

β = P (Accept H₀ | H₁ is true)

  = P [p° ≤ 0.63 | p = 0.75]

where p° is represented as <em>pI</em><em> </em>in the subsequent calculated steps below

  = P [\frac{p°-p} \sqrt{\frac{p(1-p)}{n} } }\leq \frac{0.63-p}{\sqrt{\frac{p(1-p)}{n} } } | p=0.75]

  = P [\frac{p°-0.6} \sqrt{\frac{0.75(1-0.75)}{500} } }\leq \frac{0.63-0.75}{\sqrt{\frac{0.75(1-0.75)}{500} } } ]

  = P[Z\leq\frac{0.63-0.75}{\sqrt{\frac{0.75(1-0.75)}{500} } } ]

  = P [Z ≤ -6.20]

  = Ф (-6.20)

  ≅ 0.0000 (from Cumulative Standard Normal Distribution Table).

6 0
3 years ago
The graph of f(x) shown below
bonufazy [111]

Answer:

C

Step-by-step explanation:

the "-" sign can't be true, because that would have turned the whole graph of x² upside-down. but it is not.

so, we need a positive sign for the x term.

and the whole graph is shifted to the right. so the functional value of x of F(x) is now the same that happened "earlier" (for smaller x) with G(x). so, the argument "x" is now reduced (by 3 units, as the graph is shifted right by 3 units) in the calculation compared to the original G(x) calculation.

therefore, the ...(x-3)... expression is right.

so, positive sign and "(x-3)" is only in C.

7 0
2 years ago
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