What is the value of s O-1 0 0 O 1 O no solution

What is the solution for the =.

liq [111]

Answer:

solution for n is $\frac{-13}{4}$

Step-by-step explanation:

Given an equation containing one variable n.

The equation is as follows:

$\frac{-5}{2} =\frac{3}{4} +n$

To solve for n we can subtract 3/4 from both the sides

The result is

$\frac{-5}{2} -\frac{3}{4} =n\\Take LCD as 4\\\\frac{-10-3}{4} =n$

Verify:

Substitute the answer in the given equation.

$\frac{-5}{2} =\frac{3}{4} -(\frac{13}{4} )$

Both sides equal thus proving our correctness of answer.

3 0

3 years ago

The total cost for tuition plus room and board at State University is $2,584.00. Tuition costs $100 more than twice room and boa

liq [111]

Answer:

$1756

Step-by-step explanation:

1. More = Addition

2. Twice = Multiplication by 2

3. Tuition costs $100 more than twice room and board

Tuition = 2x + 100

$2584 = (2x + 100) + x

$2584 = 3x + 100

4. Subtract 100 on both sides: $2484 = 3x

5. Divide both sides by 3: $828 = x

6. Plug it in to the tuition equation: Tuition = 2(828) + 100

= $1756

Check Work: (828*2) + 100 = $1756

$1756 + 828 = $2584

7 0

2 years ago

What are the answers to these questions

elena-s [515]

F(-1)=2
F(2)=-1
F(3)=-3

The f(x) part is the input and the stuff after is the output

4 0

3 years ago

REPOST!!!!!! 20 POINTS!!!!!!

kkurt [141]

Answer:

A

Step-by-step explanation:

according to tangent property

we get

AM=BM
AN=CN
BK=CK

Given that

AM=6
BK=4

Thus our equation is

$\rm \displaystyle 2AM + 2AN + 2BK = 34$

substitute the given values

$\rm \displaystyle 2.6+ 2AN+ 2.4 = 34$

simplify multiplication:

$\rm \displaystyle 12+ 2AN+ 8 = 34$

simplify addition:

$\rm \displaystyle 2AN+ 20= 34$

cancel 20 from both sides:

$\rm \displaystyle 2AN=14$

divide both sides by 2:

$\rm \displaystyle AN=7$

AN=CN

hence,CN=7

therefore our answer is A

6 0

2 years ago

1 point) Are the functions f,g, and h given below linearly independent? f(x)=e3x+cos(5x), g(x)=e3x−cos(5x), h(x)=cos(5x). If the

Fynjy0 [20]

Answer:

Functions are linearly dependent (are not linearly independent.)

Step-by-step explanation:

Remember that two functions f(x), g(x) and h(x) are said linearly independent on an interval I if the only solution to the equation

$\alpha f(x)+\beta g(x)+\omega h(x)=0, \ \text{for all } x\in I$

is the trivial one: α = 0, β = 0, ω = 0. If they are not linearly independent, they are called linearly dependent.

Now, let f(x), g(x) and h(x) be the functions:

$f(x)=e^{3x}+\cos(5x),$

$g(x)=e^{3x}-\cos(5x),$

$h(x)=\cos(5x).$

Then, letting α = 1, β= -1 and ω = -2, we see that:

$\alpha f(x)+\beta g(x)+ \omega h(x)=e^{3x}+\cos(5x)-e^{3x}+\cos(5x)+2\cos(5x)=0.$

Hence, the functions f(x), g(x) and h(x) are not linearly independent, or equivalently, are linearly dependent.

8 0

3 years ago