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WINSTONCH [101]
2 years ago
8

Please help me!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
Aneli [31]2 years ago
4 0

Answer:

5 times as many should be your answer.

shtirl [24]2 years ago
3 0

Answer:

2 times as many.

Step-by-step explanation:

2 times as many

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Show that in a group of five people (where any two people are either friends or enemies), there are not necessarily three mutual
sveta [45]

Answer:

Lets call the people A,B,C,D and E. We need to find an example where there are not 3 mutual friends and not three mutual enemies.

Lets start by assuming that A has 2 friends, B and C, and 2 enemies, D and E.

Since we want A,B and C not to be mutually friends, then B and C neccesarily have to be enemies.

Now, since B and C are enemies, they cant be enemies at the same time with D, and they also cant be enemies at the same time with E. Therefore one of them has to be friends with D and one has to be friends with E.

Also, since D and E are enemies with A, they neccesarily need to be friends.

From the fact that D and E are friends, we coclude that they cant have a friend in common, as a consequence, B has to be friends with one of D and E and C has to be friend with the other. We can assume that B is friend with D and C is friend with E. If we use that, we have the following friendship configuration

---------------------

Friends of A: B, C

Enemies of A: D,E

-------------------------

Friends of B: A,D

Enemies of B: C, E

------------------------

Friends of C: A,E

Enemies of C: B,D

------------------------

Friends of D: B,E

Enemies of D: A,C

----------------------------

Friends of E: C,D

Enemies of E:  A,B

--------------------------

As you can check, there is not three mutual friends nor three mutual enemies.

8 0
3 years ago
Which equation represents the polar form of x² + (y + 4)² = 16?
Paraphin [41]

x^2+y^2=r^2\hspace{5em}x=r\cos(\theta )\hspace{5em}y=r\sin(\theta ) \\\\[-0.35em] ~\dotfill\\\\ x^2+(y+4)^2=16\implies x^2+\stackrel{binomial~expansion}{y^2+8y+16}=16 \\\\\\ \underset{x^2+y^2}{r^2} + 8(~\underset{8y}{r\sin(\theta )}~)=16-16\implies r^2+8r\sin(\theta)=0 \\\\\\ r^2=-8r\sin(\theta )\implies \cfrac{r^2}{r}=-8\sin(\theta )\implies r=-8\sin(\theta )

3 0
2 years ago
How to solve -2(5n+6)+5(2-7n)
Alex Ar [27]

Answer:

-45n-2

Step-by-step explanation:

Let's get rid of parenthesis first using distributive property!

-10n-12+10-35n

Combine like terms!

-10n-35n--12+10

-45n-2 would be the final expression

5 0
3 years ago
Read 2 more answers
Which expression is equal to p + (q + r)?
Verdich [7]
The answer is letter B.
5 0
3 years ago
Read 2 more answers
Y+2=1/3 (x+1) please can you help
miskamm [114]

Equation:

y + 2 = 1/3(x+1)

Assuming you are solving for Y:

y + 2 = 1/3(x) + 1/3(1)

(y + 2) - 2 = (1/3x + 1/3) - 2

y = 1/3x + 1/3 - 2

<u>y = 1/3x - 5/3</u>

7 0
3 years ago
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