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nasty-shy [4]
2 years ago
12

Logariths, please help​

Mathematics
1 answer:
Valentin [98]2 years ago
3 0

Answer:

<em>{ - 2 , 8 } </em>

Step-by-step explanation:

log_{4} ( x² - 6x ) = 2

4² = ( x² - 6x )

x² - 6x - 16 = 0

- 6 = - 8 + 2

- 16 = - 8 * 2

( x - 8 )( x + 2 ) = 0 ⇒ x_{1} = - 2 , x_{2} = 8

<em>{ - 2 , 8 }</em>

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Let x denote the lifetime of a mcchine component with an exponential distribution. The mean time for the component failure is 25
aliina [53]

Answer:

0.1353 = 13.53% probability that the lifetime exceeds the mean time by more than 1 standard deviations

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

f(x) = \mu e^{-\mu x}

In which \mu = \frac{1}{m} is the decay parameter.

The probability that x is lower or equal to a is given by:

P(X \leq x) = \int\limits^a_0 {f(x)} \, dx

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P(X \leq x) = 1 - e^{-\mu x}

The probability of finding a value higher than x is:

P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}

The mean time for the component failure is 2500 hours.

This means that m = \frac{2500}, \mu = \frac{1}{2500} = 0.0004

What is the probability that the lifetime exceeds the mean time by more than 1 standard deviations?

The standard deviation of the exponential distribution is the same as the mean, so this is P(X > 5000).

P(X > x) = e^{-0.0004*5000} = 0.1353

0.1353 = 13.53% probability that the lifetime exceeds the mean time by more than 1 standard deviations

4 0
3 years ago
What is 74 times 98 add 65?
vitfil [10]

Answer:

7317

Step-by-step explanation:

74x98+65=7317

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3 years ago
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