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Ratling [72]
2 years ago
5

If the volume of a cuboid is 120 cm' and it has a length of 10cm, a height of 4cm, the width of the cuboid is ?

Mathematics
1 answer:
Misha Larkins [42]2 years ago
6 0

Answer:

3cm

Step-by-step explanation:

V = L * W * H

V = 10 * W * 4

10 * 4 = 40

120 / 40 = 3

W = 3

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A certain investment earns 8 3/4 compound continuously. If 10,000 dollars is invested for 5 years how much will be in the accoun
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Answer:65749

Step-by-step explanation:

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3 years ago
Find the value of the expression x3−y3+x2+y2+3 by substituting x=−2 and y=1.
vaieri [72.5K]

\\ \sf\dashrightarrow x^3-y^3+x^2+y^2+3

\\ \sf\dashrightarrow (-2)^3-(1)^3+(-2)^2+(1)^2+3

\\ \sf\dashrightarrow -8-1+4+1+3

\\ \sf\dashrightarrow -9+8

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8 0
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Read 2 more answers
Are you smarter than a second grader? A random sample of 60 second graders in a certain school district are given a standardized
denis23 [38]

Answer:

We accept H₀ , we do not have enought evidence for rejecting H₀

Step-by-step explanation:

Normal Distribution

sample size   n  =   60

standard deviation     σ  =  15

1.Hypothesis Test : Is a one tailed-test on the right

H₀      null hypothesis             μ₀  = 50

Hₐ    alternative hypothesis   μ₀  > 50

2.-We will do the test for  a significance level   α =  0,01 tht means for a 99% interval of confidence

then z(c)  =  2.32

3.- We compute z(s)  

z(s)  =  [ ( μ - μ₀ ) /( σ/√n )       ⇒  z(s)  =  (  2 * √60 ) / 15

z(s)  = 15.49/15                        ⇒   z(s)  = 1.033

4.- We compare values of  z(c)   and z(s)

z(s)  <  z(c)      1.033 < 2.32

z(s) is in the acceptance region so we accept H₀ , we do not have enough evidence for rejecting H₀

6 0
3 years ago
What binomial do you have to add to the polynomial:
marshall27 [118]

Answer:

a)  -2x^2+5xy

b)  -3y^2+5xy

Step-by-step explanation:

<u>Part (a)</u>

Given polynomial  :2x^2+3y^2-5xy+1

The binomial that should be added to the given polynomial to get a polynomial that does not contain the variable x is:

-2x^2+5xy

(2x^2+3y^2-5xy+1)+(-2x^2+5xy)

=2x^2+3y^2-5xy+1-2x^2+5xy

=2x^2-2x^2+3y^2-5xy+5xy+1

=3y^2+1

<u>Part (b)</u>

Given polynomial  :2x^2+3y^2-5xy+1

The binomial that should be added to the given polynomial to get a polynomial that does not contain the variable y is:

-3y^2+5xy

(2x^2+3y^2-5xy+1)+(-3y^2+5xy)

=2x^2+3y^2-5xy+1-3y^2+5xy

=2x^2+3y^2-3y^2-5xy+5xy+1

=2x^2+1

7 0
2 years ago
7. log(x+3)(2x + 3) +log(x+3)(x + 5) = 2
iren [92.7K]

Answer:67

Step-by-step explanation: the first one is the best. that’s why

5 0
3 years ago
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