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lara [203]
3 years ago
10

For the sequence 3, 8, 13, 18, 23, ….: (i) Find recursive and non-recursive formulas. (ii) Prove the non-recursive formula using

recursive formula and by induction. (iii) Write and iterative algorithm to out put the first m terms.
Mathematics
1 answer:
Aleksandr-060686 [28]3 years ago
7 0

Answer:

Step-by-step explanation:

Given is the sequence 3, 8, 13, 18, 23, ….:

We find that this is a geometric sequence with each term added with 5 to the previous term

Hence recursive formula is a_n =a_{n-1} +5

Non recursive formula:

a_n =a_{n-1} +5=a_{n-2} +2(5)\\=a_{n-3} +3(5)-...\\=a_{n-(n-1)} +5(n-1)\\=a_1+(n-1)5\\=3+5n-5\\=5n-2

iii) Start with 3.

Add 5 and write as 2nd term

Take the resulting term and add 5 and mark as 3rd term

Repeat this m times.

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The length of a rectaangle 48 centimeters. The relationship between the length, the width, and the perimeter of the rectangle ca
Monica [59]

Answer:

Step-by-step explanation:

We are told that the perimeter is 48 = 2L + 2W.  This reduces to

24 = L + W.  Next, substitute, one by one, the 3 widths 10 cm, 3.6 cm and w cm:

a)  If W = 10 cm, 24 = L + W becomes 24 = L + 10, or L = 14 cm

b)  If W = 3.6 cm, 24 = L + W becomes 24 = L + 3.6, or L = 20.6 cm

c)  If W = w, 24 L + W becomes 24 = L + w, so that L = (24 - w) cm

4 0
3 years ago
Enter the correct answer in the box. solve the equation x2 − 16x 54 = 0 by completing the square. fill in the values of a and b
poizon [28]

The roots of the given polynomials exist  $x=8+\sqrt{10}$, and $x=8-\sqrt{10}$.

<h3>What is the formula of the quadratic equation?</h3>

For a quadratic equation of the form $a x^{2}+b x+c=0$ the solutions are

$x_{1,2}=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Therefore by using the formula we have

$x^{2}-16 x+54=0$$

Let, a = 1, b = -16 and c = 54

Substitute the values in the above equation, and we get

$x_{1,2}=\frac{-(-16) \pm \sqrt{(-16)^{2}-4 \cdot 1 \cdot 54}}{2 \cdot 1}$$

simplifying the equation, we get

$&x_{1,2}=\frac{-(-16) \pm 2 \sqrt{10}}{2 \cdot 1} \\

$&x_{1}=\frac{-(-16)+2 \sqrt{10}}{2 \cdot 1}, x_{2}=\frac{-(-16)-2 \sqrt{10}}{2 \cdot 1} \\

$&x=8+\sqrt{10}, x=8-\sqrt{10}

Therefore, the roots of the given polynomials are $x=8+\sqrt{10}$, and

$x=8-\sqrt{10}$.

To learn more about quadratic equations refer to:

brainly.com/question/1214333

#SPJ4

3 0
1 year ago
Read 2 more answers
Which pair of triangles are congruent by ASA ?
Eddi Din [679]
Your answer is going to be letter D.)?
6 0
3 years ago
Hi can you help me in mate plis simplify the following algebraic expressions​
mars1129 [50]

Answer:

\frac{3 {x}^{2} }{ {y}^{2} {z}^{6}  }

Step-by-step explanation:

I have attached the explanation above. hopefully this will help

4 0
3 years ago
The lengths of the two sides of a triangle (not necessarily a right triangle) are 1.00 meters and 3.46 meters. The sine of the a
Hoochie [10]

Answer:

0.1228

Step-by-step explanation:

We use sine rule

\dfrac{a}{\sin A} = \dfrac{b}{\sin B} = \dfrac{c}{\sin C}

where, in any triangle <em>ABC</em>, <em>a</em> is the side opposite ∠A, <em>b</em> is the side opposite ∠B and <em>c</em> is the side opposite ∠C.

Applying this to the question,

\dfrac{1.00}{0.0355} = \dfrac{3.46}{\sin B}

\sin B = 3.46\times0.0355 = 0.12283 \approx 0.1228

7 0
3 years ago
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