Do number 1 pleaseeee

Mathematics

1 answer:

stira [4]2 years ago

5 0

Answer:Let's start b writing down coordinates of all points:A(0,0,0)B(0,5,0)C(3,5,0)D(3,0,0)E(3,0,4)F(0,0,4)G(0,5,4)H(3,5,4)a.) When we reflect over xz plane x and z coordinates stay same, y coordinate changes to same numerical value but opposite sign. Moving front-back is moving over x-axis, moving left-right is moving over y-axis, moving up-down is moving over z-axis.A(0,0,0)ReflectingA(0,0,0)B(0,5,0)ReflectingB(0,-5,0)C(3,5,0)ReflectingC(3,-5,0)D(3,0,0)ReflectingD(3,0,0)b.)A(0,0,0)MovingA(-2,-3,1)B(0,-5,0)MovingB(-2,-8,1)C(3,-5,0)MovingC(1,-8,1)D(3,0,0)MovingD(1,-3,1)

Step-by-step explanation:

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A jet’s speed in still air is 240 mph. One day it flew 700 miles with a tailwind (the wind pushing it along) and then returned t

Bess [88]

Speed of the wind for jet speed in still air 240mph and jet covers 700 miles with tailwind and same distance against the wind in total time of 6 hours is equal to 40mph.

As given in the question,

Given data:

Jet speed in still air = 240mph

Let x be the speed of the wind.

Speed with tail wind = 240 +x

Distance covered with tail wind = 700miles

Time taken by jet with tail wind

= Distance/ speed

= 700 / (240 +x) __(1)

Speed against the wind = 240 - x

Distance covered against the wind = 700miles

Time taken by jet against the wind

= Distance/ speed

= 700 / (240 - x) __(2)

Total time taken is 6 hours

[700 / (240 +x)] + [700 / (240 - x)] = 6

⇒ 700( 240 -x + 240 + x) = 6 (240 +x)(240 - x)

⇒ 700 ( 480) = 6 ( 240² -x²)

⇒ 700 (80) = 57600 -x²

⇒ x² = 57600 - 56000

⇒ x² = 1600

⇒ x = √1600

⇒ x= 40 mph

Therefore, speed of the wind for jet speed in still air 240mph and jet covers 700 miles with tailwind and same distance against the wind in total time of 6 hours is equal to 40mph.

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Find the greater ratio - 6:7 and 7:8

Shtirlitz [24]

Answer:

6:7

Step-by-step explanation:

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3 years ago