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3 years ago

How many solutions are there?

Mathematics

2 answers:

Oliga [24]3 years ago

8 0

Answer:

no solution

Step-by-step explanation:

Solve:

6(2k + 1) = 12k + 1

Expand brackets:

⇒ 12k + 6 = 12k + 1

Subtract 12k from both sides:

⇒ 6 = 1

As 6 ≠ 1 there is no solution

maw [93]3 years ago

7 0

Answer:

No solution

Step-by-step explanation:

<u>Simplify the L.H.S and the R.H.S</u>

⇒ $6(2k + 1) = 12k + 1$

⇒ $12k + 6 = 12k + 1$

<u>Cancel out the "12k"</u>

⇒ $12k + 6 = 12k + 1$

⇒ $6 = 1 (\text{False})$

Henceforth, this equation has no solution.

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