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3 years ago

4 1/5 tons = how many ponds

Mathematics

2 answers:

elena55 [62]3 years ago

5 0

Answer:

Step-by-step explanation:

21/5*2000= 21*400= 8,400 pounds

Kipish [7]3 years ago

3 0

Answer:

$\displaystyle 8400\:lbs.$

Explanation:

On United States Imperial [Customary] System, there is one ton in two thousand pounds. So, because we are going from a bigger unit of measurement to a smaller unit of measurement, we multiply the quantity of tons by two thousand:

$\displaystyle \boxed{8400} = 2000[4\frac{1}{5}]$

I am joyous to assist you at any time.

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Plz help it's due till 12.06

larisa [96]

Answer:

Step-by-step explanation:

the different planes are either negitive or positive. since one goes to positive and negative, for example, 5 is greater that -9.

4 0

3 years ago

Read 2 more answers

BRAINLIEST PLUS POINTS

vovangra [49]

Answer:

a) e(0,2)

b) 1

c) read below

d) read below

Step-by-step explanation:

Midpoint:

to calculate the midpoint e of a segment

e((x1+x2)/2, (y1+y2)/2)

so (-1+1)/2 and (3+1)/2

e(0,2)

Slope formula:

the slope of a straight line between two points is

$\frac{y_2-y_1}{x_2-x_1}$

so between e and B it's equal to (4-2)/(2-0) = 1

Condition for perpendicularity : slope(AC) = -1/slope(eB) = -1

so we calculate the slope of a straight line through A and C

(1-3)/1-(-1) = -2/2 = -1 so they are perpendicular

Area:

eB is the height of the triangle as it's perpendicular to the base, so applying the standard formula Area = (AC*eB)/2 we can find the area

6 0

3 years ago

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Enter the solution to the equation in the box. 5(x−8)=7(x−4) x =

sladkih [1.3K]

Here you go ! Please give me a thank

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3 years ago

Find the equation of the line . Write in slope intercept form and in standard form. (SHOW YOUR SOLUTION)

AlladinOne [14]

Answer:

1) The slope-intercept and standard forms are $y = -5\cdot x + 1$ and $5\cdot x +y = 1$ , respectively.

2) The slope-intercept form of the line is $y = \frac{5}{2}\cdot x -\frac{9}{2}$ . The standard form of the line is $-5\cdot x +2\cdot y = -9$ .

3) The slope-intercept form of the line is $y = \frac{5}{2}\cdot x + 5$ . The standard form of the line is $-5\cdot x +2\cdot y = 10$ .

4) The slope-intercept and standard forms of the family of lines are $y = \frac{2}{7}\cdot x -\frac{c}{7}$ and $2\cdot x -7\cdot y = c$ , $\forall \,c \in \mathbb{R}$ , respectively.

5) The slope-intercept form of the line is $y = 2\cdot x-7$ . The standard form of the line is $-2\cdot x +y = -7$ .

Step-by-step explanation:

From Analytical Geometry we know that the slope-intercept form of the line is represented by:

$y = m\cdot x + b$ (1)

Where:

$x$ - Independent variable, dimensionless.

$m$ - Slope, dimensionless.

$b$ - y-Intercept, dimensionless.

$y$ - Dependent variable, dimensionless.

In addition, the standard form of the line is represented by the following model:

$a\cdot x + b \cdot y = c$ (2)

Where $a$ , $b$ are constant coefficients, dimensionless.

Now we process to resolve each problem:

1) If we know that $m = -5$ and $b = 1$ , then we know that the slope-intercept form of the line is:

$y = -5\cdot x + 1$ (3)

And the standard form is found after some algebraic handling:

$5\cdot x +y = 1$ (4)

The slope-intercept and standard forms are $y = -5\cdot x + 1$ and $5\cdot x +y = 1$ , respectively.

2) From Geometry we know that a line can be formed by two distinct points on a plane. If we know that $(x_{1},y_{1})=(1,-2)$ and $(x_{2},y_{2}) = (3,3)$ , then we construct the following system of linear equations:

$m+b= -2$ (5)

$3\cdot m +b = 3$ (6)

The solution of the system is:

$m = \frac{5}{2}$ , $b = -\frac{9}{2}$

The slope-intercept form of the line is $y = \frac{5}{2}\cdot x -\frac{9}{2}$ .

And the standard form is found after some algebraic handling:

$-\frac{5}{2}\cdot x +y = -\frac{9}{2}$

$-5\cdot x +2\cdot y = -9$ (7)

The standard form of the line is $-5\cdot x +2\cdot y = -9$ .

3) From Geometry we know that a line can be formed by two distinct points on a plane. If we know that $(x_{1},y_{1})=(-2,0)$ and $(x_{2},y_{2}) = (0,5)$ , then we construct the following system of linear equations:

$-2\cdot m +b = 0$ (8)

$b = 5$ (9)

The solution of the system is:

$m =\frac{5}{2}$ , $b = 5$

The slope-intercept form of the line is $y = \frac{5}{2}\cdot x + 5$ .

And the standard form is found after some algebraic handling:

$-\frac{5}{2}\cdot x+y =5$

$-5\cdot x +2\cdot y = 10$ (10)

The standard form of the line is $-5\cdot x +2\cdot y = 10$ .

4) If we know that $a = 2$ and $b = -7$ , then the standard form of the family of lines is:

$2\cdot x -7\cdot y = c$ , $\forall \,c \in \mathbb{R}$

And the standard form is found after some algebraic handling:

$-7\cdot y = -2\cdot x +c$

$y = \frac{2}{7}\cdot x -\frac{c}{7}$ , $\forall \,c\in\mathbb{R}$ (11)

The slope-intercept and standard forms of the family of lines are $y = \frac{2}{7}\cdot x -\frac{c}{7}$ and $2\cdot x -7\cdot y = c$ , $\forall \,c \in \mathbb{R}$ , respectively.

5) If we know that $(x,y) = (3,-1)$ and $m = 2$ , then the y-intercept of the line is: