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Darina [25.2K]
3 years ago
15

An amusement park has 32000 visitors per day when it charges $70 per person. For each $2 increase in price, the park loses about

800 visitors answer. How much should the park charge to maximize the daily revenue? What is the maximum daily revenue?
Mathematics
1 answer:
Bumek [7]3 years ago
6 0

Answer:

Maximum daily revenue = $2,249,600

Step-by-step explanation:

If you approach this problem with a trail and error mindset you can quickly calculate that if you take an increase of $6  per ticket or $76 per ticket, then subtract the equivalent loss of visitors which would be 800 * 3 or 2,400 then you get 29,600 visitors. By simply multiplying this number by the cost of the tickets you achive  2,249,600 daily. This could be wrong as I did not use a formula.    

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