Given:
The perimeter of a rhombus of side d cm is
To find:
The perimeter of a rhombus of side 3.2 cm.
Find the length of a side of a rhombus of perimeter 14 cm.
Solution:
Side of a rhombus is 3.2 cm. So, its perimeter is
Therefore, the perimeter of a rhombus of side 3.2 cm is 12.8 cm.
The perimeter of another rhombus is 14 cm, and we need find its side.
Divide both sides by 4.
Therefore, the length of a side of a rhombus of perimeter 14 cm is 3.5 cm.
Answer:
x²+y² = 64
Step-by-step explanation:
The standard form of writing the equation of a circle is expressed as;
(x-a)²+(y-b)² = r² where;
(a, b) is the centre of the circle
r is the radius of the circle
Given the diameter of the circle with endpoints (8,0) and (-8, 0)
d = √(x2-x1)²+(y2-y1)²
d = √(-8-8)²+(0-0)²
d = √(-16)²
d = √256
d = 16
radius r = 16/2
r = 8
The centre of the circle will be the midpoint of the coordinates
M = (8-8/2, 0+0/2)
M = (0/2, 0/2)
M = (0,0)
Hence the centre is at (0,0)
Get the required equation
Recall that (x-a)²+(y-b)² = r²
Substitute the centre and the radius
(x-0)²+(y-0)² = 8²
x²+y² = 64
This gives the required equation
Answer:
Similarities:
- Both transactions have a magnitude of $25.
- Both transactions result in a change of $25 in the account.
- The absolute value is the same ($25).
Differences:
- The two transactions yield opposite results.
Step-by-step explanation:
A $25 credit results in a positive action in the account while the $25 charge is a negative action on the account.
Maybe 200 dollars, 500 dollars and so on
