Answer:
2.94 x 10⁵ Pa
Explanation:
m = mass of the car supported by four ires = 1200 kg
g = acceleration due to gravity = 9.8 m/s²
A = Area of contact for each tire = 100 cm² = 100 x 10⁻⁴ m²
n = Number of tires
P = Gauge pressure
Using equilibrium of force in vertical direction
n P A = mg
4 P (100 x 10⁻⁴) = (1200) (9.8)
P = 2.94 x 10⁵ Pa
Answer:
51.04 joules
Explanation:
The movement by the gloves = 11cm
Force by the baseball = 464N
First of all we are going to convert cm to metres
11cm = 11/100 meters = 0.11m
The formula for workdone is given as:
W = f x d
W = workdone
F = force
D = distance
Workdone = 464 x 0.11
= 51.04 joules
The workdone by the ball is 51.04 joules
Thank you
<span>The x component of velocity is 9.0m/s, y component is zero initially.</span><span>a = -9.8m/</span><span>s2</span>
Since the jumper lands at a -45-degree angle the final Vy must have the same magnitude as the final Vx. <span>V<span>f2 </span>= V<span>02 </span>+ 2ad</span>Plugging in values:<span>(−9.0m/s<span>)2</span>=0m/s+2(−9.8m/<span>s2</span>)d</span><span>The height difference,d is equal to |-4.13| or 4.13 m.</span>
Answer:
25 psi
Explanation:
The weight of the car is:
W = mg
W = 1550 kg * 9.8 m/s²
W = 15,190 N
Divided by 4 tires, each tire supports:
F = W/4
F = 15,190 N / 4
F = 3797.5 N
Pressure is force divided by area, so:
P = F / A
P = (3797.5 N) / (0.16 m × 0.14 m)
P ≈ 170,000 Pa
101,325 Pa is the same as 14.7 psi, so:
P ≈ 170,000 Pa × (14.7 psi / 101,325 Pa)
P ≈ 25 psi
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