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2 years ago

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What is the definition for Astrology?

1 answer:

Kay [80]2 years ago

3 0

Astrology is the belief the positions of the stars and movements of the planets of the Solar System, and also asteroids and other stars, but not as much, have an influence on the events, lives, and behavior of people.

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To measure the strength of an earthquake, you can use either a _____ scale or _____ scale.

allsm [11]

To measure the strength of an earthquake, you can use either a Richter scale or Mercalli scale. Richter scale uses the amplitued of the wave and the distance from the source. Mercalli scale uses observations of people and is not considered to be scientific as Richter scale.

8 0

3 years ago

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Charge g is distributed in a spherically symmetric ball of radius a. (a) Evaluate the average volume charge density p. (b) Now a

nasty-shy [4]

Answer:

Explanation:

The volume of a sphere is:

V = 4/3 * π * a^3

The volume charge density would then be:

p = Q/V

p = 3*Q/(4 * π * a^3)

If the charge density depends on the radius:

p = f(r) = k * r

I integrate the charge density in spherical coordinates. The charge density integrated in the whole volume is equal to total charge.

$Q = \int\limits^{2*\pi}_0\int\limits^\pi_0 \int\limits^r_0 {k * r} \, dr * r*d\theta* r*d\phi$

$Q = k *\int\limits^{2*\pi}_0\int\limits^\pi_0 \int\limits^r_0 {r^3} \, dr * d\theta* d\phi$

$Q = k *\int\limits^{2*\pi}_0\int\limits^\pi_0 {\frac{r^4}{4}} \, d\theta* d\phi$

$Q = k *\int\limits^{2*\pi}_0 {\frac{\pi r^4}{4}} \, d\phi$

$Q = \frac{\pi^2 r^4}{2}}$

Since p = k*r

Q = p*π^2*r^3 / 2

Then:

p(r) = 2*Q / (π^2*r^3)

3 0

2 years ago

A material that can easily flow is called a

murzikaleks [220]

A material that can easily flow is called a...

A. Fluid.

3 0

3 years ago

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The unit of current, the ampere, is defined in terms of the force between currents. Two 1.0-meter-long sections of very long wir

Paha777 [63]

Answer:

1.6 x $10^{-7}$ N

Explanation:

If the force between two actual wires has this value, the current is defined to be exactly 1 A.

The force between two parallel wires carrying current can be defined as,

F= μ $I_{1}$ $I_{2}$ L/ 2πd

where,

current $I_{1}$ = 1Amp

current $I_{2}$ = 2amp

Length 'L'= 1m

distance 'd'= 2.5m

permeability of free space 'μ'= 4πx $10^{-7}$ N/m

Putting the above values in the equation,

F=( 4πx $10^{-7}$ x 1 x 2 x 1 )/ 2πx2.5

F= 1.6 x $10^{-7}$ N

8 0

3 years ago

ASK YOUR TEACHER Red blood cells often can be charged. Two red blood cells are separated by 1.11 m and have an attractive electr

makvit [3.9K]

Answer:

q2 = -1.61*10^-5 C.

Explanation:

It was given that,

F = 0.985N

q1 = +8.40 X10-6 C

q2 = ?

r = 1.11 m

k = 9 x 10^9 (standard)

It generally follows that, if force is attractive, charge will be negative.

force, F = kq1q2/r^2

0.985 = 9*10^9*8.40*10^-6*q2/1.11^2

75600q2 = 0.985*1.11^2

75600q2 = 1.2136

q2 = 1.2136/75600 = 1.60529

q2 = -1.61*10^-5 C.

7 0

3 years ago

Read 2 more answers