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Rasek [7]
3 years ago
15

What is the definition for Astrology?

Physics
1 answer:
Kay [80]3 years ago
3 0
Astrology is the belief the positions of the stars and movements of the planets of the Solar System, and also asteroids and other stars, but not as much, have an influence on the events, lives, and behavior of people.
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Which statement best describes wavelength?
xxMikexx [17]

Answer:

B

Explanation:

Wave length is the height perpendicular verically of a wave

5 0
2 years ago
Read 2 more answers
Please help i'm going to throw up from stress
Eddi Din [679]

Answer:

Explanation:

First of all, I used the specific heat of water as 4182 J/(kgC) and the specific heat of ethyl alcohol (EtOH) as 2440 J/(kgC); that means that we need the masses in kg, not g.

120.g = .1200 kg of ethyl alcohol. Now for the formula:

t_f=\frac{(m_{H2O}*spheat_{H2O}*temp_{H2O})+(m_{EtOH}*spheat_{EtOH}*temp_{EtOH})}{(m_{H2O}*spheat_{H2O})+(m_{EtOH}*spheat_{EtOH})} where spheat is specific heat.

Filling that horrifying-looking formula in with some values:

16.0=\frac{(x*4182*20.0)+(.1200*2440*10.0)}{(x*4182)+(.1200*2440)} and

16.0=\frac{83640x+2928}{4182x+292.8} and

16(4182x + 292.8) = 83640x + 2928 and

66912x + 4684.8 = 83640x + 2928 and

1756.8 = 16728x so

x = .105 kg and the amount of water added is 105 g

4 0
3 years ago
Hope you all doing okay
Vsevolod [243]

Answer:Thank you

Explanation:

8 0
2 years ago
Two capacitors with capacitances of 3.25 and 5.00 μF, respectively, are connected in parallel. The system is connected to a 55-V
Nataliya [291]

The charge accumulated in 3.25 μF capacitor is 178.75 μC.

Answer:

Explanation:

In parallel connection, the voltage drop across any passive devices like capacitor or resistor will be constant. So the current flow will be varying in case of parallel connections of capacitors or resistors.

As the capacitance is the measure of amount of charge or current generated for a given amount of voltage, it is directly proportional to the charge or current and inversely proportional to voltage.

C = Q/V

Here the charge accumulated in a capacitor of capacitance 3.25 microfarad need to be determined which is in parallel connection with another capacitor. So the voltage through both the capacitor will be equal to the voltage of the battery which is stated as 55 V.

3.25×10^{-6} = Q/55

Q = 3.25 * 55 = 178.75 μC

So the charge accumulated in 3.25 μF capacitor is 178.75 μC.

7 0
4 years ago
7. The net force on an object at terminal velocity is what? Draw a Free Body Diagram to show you understand this idea using 2 fo
mezya [45]

Answer:

see attached

Explanation:

7 0
4 years ago
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