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Nookie1986 [14]
3 years ago
5

Determine the oreadred pair for (-10,3) whenitn it has been reflected over the y-axis

Mathematics
1 answer:
Zina [86]3 years ago
8 0

Answer:

I determined it's cherry pie because the typical slice size allows 10 slices and that is enough for 10 people to enjoy it's goodness quite amazing

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Simplify the product. (5 − 6)(2 + 7)
Nat2105 [25]
5 - 6 = -1
2 + 7 = 9
-1 × 9 = -9

-9 would be the simplified answer.

Hope this helps!
8 0
3 years ago
Mr Nelson paid $3.84 tax he pay the sales tax rate of 8% how much was item he was buying before sales tax was added ​
UkoKoshka [18]

Answer:

Mr. Nelson paid $48 befor tax.

Step-by-step explanation:

Let x be the price of the item before tax.

108 % * x - x = 3.84 (the tax itself)

27/25x - x = 3.84

2/25 x = 3.84

x = 48

3 0
3 years ago
Julie will build a rectangular pen for her dog against a barn. A wall from the barn will form one side of the pen. She has 32 m
MAXImum [283]

Answer:

<h3> The width (side perpedicular to the barn):  <u>x = 8 m</u></h3><h3>      The lenght (side parallel to the barn):  <u>y = 16 m</u> </h3>

Step-by-step explanation:

x  - the width of the barn

She has 32 m of fencing so for the lenght remain (32-2x) m of fencing:

y = 32 - 2x

Area of the fencing:  A = x•y

A(x) = x•(32 - 2x)

A(x) = -2x² + 32x             ←  quadratic function

The maximum value of quadratic function occurs at:  x=-\frac b{2a}

a = -2,  b = 32

x=-\frac b{2a}=-\frac{32}{2\cdot(-2)}=-(-8)=8

32-2x = 32 - 2•8 = 16

4 0
3 years ago
Given a standard deck of 52 cards, 3 cards are dealt without replacement. Using this situation, answer the questions below.&lt;b
kherson [118]
Given that <span>3 cards are dealt without replacement in a </span><span>standard deck of 52 cards.

Part A:

There are 4 queens in a standard deck of 52 card, thus the probability that the first card is a queen is given by 4 / 52 = 1 / 13.

Since, the first card is not replaced, thus there are 3 queens remaining and 51 ards remaining in total, thus the probability that the second card is a queen is given</span> by 3 / 51 = 1 / 17

Similarly the probability that the third card is a queen is given by 2 / 50 = 1 / 25.

Therefore, the probability that <span>all three cards are queens is given by

\frac{1}{13} \times \frac{1}{17} \times \frac{1}{25} = \frac{1}{5525}



Part B:

Yes the probability of drawing a queen of heart is independent of the probability of drawing a queen of diamonds because they are separate cards and drawing one of the cards does not in any way affect the chance of drawing the other card.



Part C:

Given that the first card is a queen, then there are 3 queens remaining out of 51 cards remaining, thus the number of cards that are not queen is 51 - 3 = 48 cards.

Therefore, </span>if the first card is a queen, the probability that the second card will not be a queen is given by 48 / 51 = 16 / 17



Part D:

<span>Given that the first two card are queens, then there are 2 queens remaining out of 50 cards remaining.

Therefore, </span>if two of the three cards are queens ,<span>the probability that you will be dealt three queens</span> is given by 2 / 50 = 1 / 25 = 0.04



Part E:

<span>Given that the first two card are queens, then there are 2 queens remaining out of 50 cards remaining, thus the number of cards that are not queen is 50 - 2 = 48 cards.

Therefore, </span>if two of the three cards are queens ,the probability that the other card is not a queen is given by 48 / 50 = 24 / 25 = 0.96
8 0
4 years ago
The Robot Factory is a learning center where children can build robots. The project fee per visit is $18, and each hour of time
ipn [44]
The answer is 2 and a half. Because 18 + 6 + 6 + 3 is 33. This is because $18 to get in then $6 for one hour another $6 for an hour and $3 for an half hour.
5 0
4 years ago
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