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3 years ago

alex is building a circular base for a fountain. The radius of the circle is 4 ft. what is the area of the base ?

1 answer:

7 0

The area of a circle is measure by
A=pi(r)^2
So we would do
Area= pi(4)^
ANSWER
Area=16pi
Area is about=50.24 if using 3.14 as pi

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When you subtract one equation from the other what is the value of x

sweet [91]

Answer:

uh depends on the equations

6 0

3 years ago

3/4w=9 what does w equal?

Studentka2010 [4]

3/4 w = 9

multiply by 4/3 on both sides

4/3 x 3/4 w = 9 x 4/3

w = 9 x 4/3

Simplify that

w = 3 x 4

w = 12

So your final answer is

$\boxed{\bf{w=12}}$

5 0

2 years ago

Read 2 more answers

Find the coordinates of point b on ac such that the ratio of AB to BC is 2:1

riadik2000 [5.3K]

Answer:

(-2, 3)

Step-by-step explanation:

the point B is

B(x,y)

AB (A to B) is twice BC ( B to C )

AB is 2 - x. BC is x - (-4)= x + 4

2-x=2 (x + 4)

2-x=2x + 8

3x = -6

x = -2

(Same logic as above)

AB is -5 -y. BC is u - 7

-5 -y = 2(y - 7)

-5 - y = 2y - 14

3y = 9

y= 3

the point is (-2, 3)

5 0

3 years ago

Make v the subject of the formula in H=m(v²-u²)/2gx

goldfiish [28.3K]

Answer:

$v=\sqrt{\dfrac{H\times 2gx}{m}+u^2}$

Step-by-step explanation:

The given formula is :

$H=\dfrac{m(v^2-u^2)}{2gx}$

We need to find the formula for v.

Cross multiplying the given formula.

$H\times 2gx=m(v^2-u^2)$

Dividing both sides by m. So,

$\dfrac{H\times 2gx}{m}=\dfrac{m(v^2-u^2)}{m}\\\\(v^2-u^2)=\dfrac{H\times 2gx}{m}$

Adding both sides by u².

$(v^2-u^2)+u^2=\dfrac{H\times 2gx}{m}+u^2\\\\v^2=\dfrac{H\times 2gx}{m}+u^2\\\\\text{So},\\\\v=\sqrt{\dfrac{H\times 2gx}{m}+u^2}$

Hence, this is the required formula.

4 0

2 years ago

The square below has an area of

Solnce55 [7]

Answer:

8-x meters

Step-by-step explanation:

Both 64 and x^2 are perfect squares, since 64=(8)^2 and x^2=(x)^2.

Additionally, 16x is twice the product of the roots of 64 and x^2, since 16x=2(8)(x).

So we can use h the square of a difference pattern to factor:

a^2-2(a)(b)+b^2=(a-b)^2

In this case, a=8 and b=x:

(8)^2-2(8)(x)+(x)^2=(8-x)^2

In conclusion...

64-16x+x^2=(8-x)^2

So the side length of the square is 8-x meters.

3 0

3 years ago