I am pretty sure its B (minimum at -1, -4) because that would be were the first point would be at. The Graphing of this equation would be a "upside down u" shape.
We have that
<span>tan(theta)sin(theta)+cos(theta)=sec(theta)
</span><span>[sin(theta)/cos(theta)] sin(theta)+cos(theta)=sec(theta)
</span>[sin²<span>(theta)/cos(theta)]+cos(theta)=sec(theta)
</span><span>the next step in this proof
is </span>write cos(theta)=cos²<span>(theta)/cos(theta) to find a common denominator
so
</span>[sin²(theta)/cos(theta)]+[cos²(theta)/cos(theta)]=sec(theta)<span>
</span>{[sin²(theta)+cos²(theta)]/cos(theta)}=sec(theta)<span>
remember that
</span>sin²(theta)+cos²(theta)=1
{[sin²(theta)+cos²(theta)]/cos(theta)}------------> 1/cos(theta)
and
1/cos(theta)=sec(theta)-------------> is ok
the answer is the option <span>B.)
He should write cos(theta)=cos^2(theta)/cos(theta) to find a common denominator.</span>
Answer:
The correct option is B.
Step-by-step explanation:
Two triangle are similar if their corresponding sides are in the same proportion or the corresponding angles are same.
It is given that the ΔPQR is similar to ΔPTS. It means all corresponding angles are same.
Angle P can be defined as
Therefore option B is correct.
Therefore option A, C and D are incorrect.
Answer:
Option H, π/3 and 2π/3
Step-by-step explanation:
sin x = sqrt(3) / 2
<em>It happens at 60 degrees and 120 degrees. In radians, it is π/3 and 2π/3</em>
<em />
Answer: Option H, π/3 and 2π/3
