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Leya [2.2K]
3 years ago
10

This one as well. Thanks! #22 a & b ​

Mathematics
2 answers:
artcher [175]3 years ago
8 0

Answer:

  • y' = 90x +33
  • y' = -4/(2x +3)^3

Step-by-step explanation:

The chain rule says ...

  dy/dx = (dy/du)·(du/dx)

For these problems that means ...

a. dy/dx = (10u +1)·(3) = 10((3x +1) +1)(3) = 3(30x +11)

  dy/dx = 90x + 33

___

b. dy/dx = -2u^-3·(2)

  dy/dx = -4/(2x +3)^3

Goshia [24]3 years ago
3 0

22a. Answer: y' = 90x + 33

<u>Step-by-step explanation:</u>

y = 5u² + u - 1       u = 3x + 1

First take the derivative of y = 5u² + u - 1 with respect to u \bigg(\dfrac{dy}{du}\bigg)

y' = (2)(5u)(u') + (1)(u') - 0

   = (10u)u' + u'

Next, take the derivative of u = 3x + 1 with respect to x  \bigg(\dfrac{du}{dx}\bigg)

u' = 3 + 0

u' = 3

Now, input u = 3x + 1 and u' = 3 into the y' equation:

y' = (10u)u' + u'

  = 10(3x + 1)(3) + 3

  = 30(3x + 1) + 3

  = 90x + 30 + 3

  = 90x + 33

***********************************************************************

22b. Answer: \bold{y'=-\dfrac{4}{(2x+3)^{3}}}

<u>Step-by-step explanation:</u>

y=\dfrac{1}{u^2}      u = 2x + 3

\text{We can rewrite y as }y=u^{-2}\\\text{Take the derivative of }y=u^{-2}\text{ with respect to u}\ \bigg(\dfrac{dy}{du}\bigg)\\\\y'=(-2)(u^{-3})(u')

Next, take the derivative of u = 2x + 3 with respect to x  \bigg(\dfrac{du}{dx}\bigg)

u' = 2 + 0

u' = 2

Now, input u = 2x + 3 and u' = 2 into the y' equation

y'=(-2)(2x+3)^{-3}(2)\\\\y'=-4(2x+3)^{-3}\\\\y'=-\dfrac{4}{(2x+3)^{3}}

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The volumes of two spheres are in a ratio of 1:8 what is the eatio rafi
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Remark
I take it that you want to know the ratio of the radii. If this is not correct, leave a comment below my answer.

You could do this by giving the spheres a definite volume, like 1 and 8 and then solve for r for one of them and then use the other sphere to find it's radius. It is not exactly the best way, and if you are going to to a physics class you want to be doing this using cancellation. 

Step One 
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\frac{V_1}{V_2} =  \frac{1}{8}

Step Two
Setup the equation for V1/V2 using the definition for a sphere. V = 4/3 pi r^3

\dfrac{1}{8} =  \frac{ \frac{4}{3} \pi( r_1)^3 }{ \frac{4}{3} \pi( r_2)^3 }

Step Three
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You are left with 1/8 = (r1)^3/ (r2)^3

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8 0
3 years ago
The length of the shadow of a pole on level ground increases by 90m when the angle of elevation of the sun changes from 58° to 3
siniylev [52]
<h3>Answer: Approximately 119.76 meters</h3>

===================================================

Work Shown:

x = starting length of the shadow

y = height of the pole

tan(angle) = opposite/adjacent

tan(58) = y/x

1.6003345 = y/x

1.6003345x = y

x = y/1.6003345

x = (1/1.6003345)y

x = 0.62486936y

-------------------------

When the angle changes, the adjacent side gets 90 meters longer

tan(angle) = opposite/adjacent

tan(36) = y/(x+90)

0.72654253 = y/(0.62486936y+90)

0.72654253(0.62486936y+90) = y

0.453994166y + 65.3888277 = y

65.3888277 = y-0.453994166y

65.3888277 = 0.546005834y

0.546005834y = 65.3888277

y = 65.3888277/0.546005834

y = 119.758478075162

y = 119.76

The height of the pole is about 119.76 meters.

8 0
3 years ago
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