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adoni [48]
3 years ago
12

A virus is a A) host. B) producer. C) consumer. D) intracellular parasite.

Mathematics
2 answers:
vredina [299]3 years ago
7 0

Answer: it’s a intracellular parasite

Step-by-step explanation: a virus will invade a host and typically latch on to red blood cells (if the virus needs a animal or human host) and inject its genes into it, using the red blood cell as a brooding ground for more of the virus which they go on an latch to more blood cells and so forth.

ella [17]3 years ago
5 0

Answer:

A virus is a D) intracellular parasite.

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Four less than the difference of a number x, squared and 6; X=2
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(x,-4) and (2,8): m = -3 find the missing value. it is in slope formula.
Snezhnost [94]

Answer:

The value of x = 6

Step-by-step explanation:

Given

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  • The point (2,8)

To determine

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Using the formula

Slope = m =  [y₂ - y₁] /  [x₂ - x₁]

here:

  • (x₁, y₁) = (x, -4)
  • (x₂, y₂) = (2, 8)
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so substitute (x₁, y₁) = (x, -4) , (x₂, y₂) = (2, 8)  and m = -3

m =  [y₂ - y₁] /  [x₂ - x₁]

-3 =  [8 - (-4)] / [2 - x]

-3 = [12] / [2-x]  

-3 (2-x) = 12

-6+3x = 12

3x = 12+6

3x = 18

divide  both sides by 3

3x/3 = 18/3

x = 6

Therefore, the value of x = 6

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mel-nik [20]
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Imagine a recessive mutation in rabbits that causes wiry fur (whereas the dominant, normal allele causes fluffy fur). If two het
arsen [322]

Answer: the required probability is  0.03516

Step-by-step explanation:

Given the data in the question;

let F represent dominant allele that causes fluffy fur and

f represent corresponding recessive allele that causes wiry fur

here are the possible genotypes and corresponding phenotypes;

FF = Fluffy fur

Ff = Fluffy fur

ff = Wiry fur

genotype of parents is Ff and Ff

and there cross will be; Ff x Ff

now Offspring will be;

                                   F                      f

F                                FF                    Ff

f                                 Ff                     ff

so the probability that the offspring will have fluffy fur = 3/4

and the probability that the offspring will have wiry fur = 1/4

The probability that the first 2 out of 4 offspring will have fluffy fur will be;

⇒ 3/4 × 3/4 × 1/4 × 1/4 =  0.03516

 Therefore, the required probability is  0.03516

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