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lidiya [134]
3 years ago
6

Sebastian swam laps everyday in the community swimming pool. he swam for 45 minutes everyday ,5 days each week , for 12 weeks. i

n that time he swam 1,800 laps. what was his average rate in laps per hour ??? what do i do ? how do i show work ??
Mathematics
2 answers:
lorasvet [3.4K]3 years ago
7 0
Ok! So this problem may seem a little tricky, but it is actually easy!

So as you read the problem you see that he swims 45 minutes everyday for 5 days. So you multiply 45 by 5 and you get 225.

Next, the question reads that he swam 5 days a week for 12 weeks. So you would multiply 225 by 12 and you get 2,700. 

Now 2,700 is how many minutes he swam for 12 weeks. Now we need to convert that into hours. 

So since there is 60 minutes in an hour, you would divide 2,700 by 60 and you get 45.

Now the question once you to find his average laps per hour. He swam 1,800 laps in 45 hours. So you will simply divide 1,800 by 45 and you get...

40! 

So Sebastian swims an average of 40 laps per hour! Yipee!

Ratling [72]3 years ago
6 0
First multiply to find the total number of hours he swam.
5(12)(.75)= 45 hours    *** the .75 represents 3/4 of a hour

1800 laps/45 hours = 40 laps per hour (average rate)
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A toy company has determined that the revenue generated by a particular toy is modeled by the following equation:
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R(x) = 11x - 0.025x^2
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3 years ago
Determine whether the points lie on straight line.
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Answer:

A) Non-collinear- does not lies on straight line

B) Collinear- lie on straight line

Step-by-step explanation:

We have to check collinearity of three points.

The points (x_1, y_1, z_1),(x_2, y_2, z_2),(x_3, y_3, z_3) are said to be collinear if,

\left[\begin{array}{ccc}x_1&y_1&z_1\\x_2&y_2&z_2\\x_3&y_3&z_3\end{array}\right] = 0

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\left[\begin{array}{ccc}2&5&3\\3&7&1\\1&4&4\end{array}\right] \\\\=2(28-4)-5(12-1)+3(12-7)\\= 8 \neq 0

Thus, the given points are not collinear.

B) D(0,-5,5), E(1,-2,4), F(3,4,2)

\left[\begin{array}{ccc}0&-5&5\\1&-2&4\\3&4&2\end{array}\right] \\\\=0(-4-16)+5(2-12)+5(4+6)\\=0

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Hence, the two-week combined profit is $25.00

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