The answer to your question: 5 - 6t
why it’s saying for each number for 6 so what ever number times 6 is t
If tan theta is -1, we know immediately that theta is in either Quadrant II or Q IV. We need to focus on Q IV due to the restrictions on theta.
Because tan theta is -1, the ray representing theta makes a 45 degree angle with the horiz axis, and a 45 degree angle with the negative vert. axis. Thus the hypotenuse, by the Pythagorean Theorem, tells us that the hyp is sqrt(2).
Thus, the cosine of theta is adj / hyp, or +1 / sqrt(2), or [sqrt(2)]/2
The secant of theta is the reciprocal of that, and thus is
2 sqrt(2)
---------- * ------------ = sqrt(2) (answer)
sqrt(2) sqrt(2)
Find the minimum, first quartile, median, third quartile, and maximum of each data set, 12, 10, 11, 7, 9, 10, 5
Sliva [168]
To find the median:
Least to greatest order:
5, 7, 9, 10, 10, 11, 12
10 is the number in the middle. Therefore the median is 10
Answer:c
Step-by-step explanation:
The Answer is C.
Answer:
Sₙ=3(1/2^n)
Step-by-step explanation:
Notice that in the given series that each term is being multiplied by 1/2, which is our common ratio. 3/2 is the first term because 3*1/2=3/2, so the expression that defines Sₙ is Sₙ=3(1/2^n)
