Answer:
How many drinks should be sold to get a maximal profit? 468
Sales of the first one = 345 cups
Sales of the second one = 123 cups
Step-by-step explanation:
maximize 1.2F + 0.7S
where:
F = first type of drink
S = second type of drink
constraints:
sugar ⇒ 3F + 10S ≤ 3000
juice ⇒ 9F + 4S ≤ 3600
coffee ⇒ 4F + 5S ≤ 2000
using solver the maximum profit is $500.10
and the optimal solution is 345F + 123S
Answer:
Step-by-step explanation:
discriminant=5²-4×1×7=25-28=-3<0
no real number solution.
Answer:
69
Step-by-step explanation:
5(
–
q+6)=
–
20
5q–30=
–
20
Add -5 to both sides
Subtract -5 from both sides
Multiply both sides by -5
Divide both sides by -5
Apply the distributive property
5q=
Add 30 to both sides
q=
Divide both sides by 5 would be 69
Answer:
54
Step-by-step explanation:
6x + 5x = 99
11x = 99
x=99/11
x=9
6x = 6x9 = 54
5x = 5x9 = 45
<em>ans: </em><u><em>54</em></u>
You have to do 10•10•10•10•10 (multiply 10, 5 times). Once you multiply 10 five times, you end up with an answer of 100,000 pencils in each box. Then since you have 6 boxes of pencils you have to multiply 100,000•6, which equals 600,000 pencils total.
