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Pavlova-9 [17]
2 years ago
12

Please help! Will mark brainliest <3. (Click on the photo too see the question!) you need to select all angle pairs that are

vertical angles.

Mathematics
2 answers:
wariber [46]2 years ago
7 0

Answer:

B and D

Step-by-step explanation:

vertical angles are ones that are formed by intersecting lines, and they are also equal to each other and opposite of each other.

its not A because they are not equal to each other.

B is correct because they are formed by intersecting line and equal to each other

C is incorrect since theres some random line that doesnt completely pass through on either side

D is correct

sattari [20]2 years ago
4 0

Answer:

☐ \displaystyle \textcolor{blue}{A.}\:\angle{S}\:and\: \angle{J}

☑ \displaystyle \textcolor{blue}{B.}\:\angle{G}\:and\: \angle{M}

☐ \displaystyle \textcolor{blue}{C.}\:\angle{H}\:and\: \angle{P}

☑ \displaystyle \textcolor{blue}{D.}\:\angle{R}\:and\: \angle{U}

Explanation:

Accourding to the Vertical Angles Theorem, vertical angles are considered congruent. So, we need to make sure we find all pairs of angles that <em>reflect</em> each other like a mirror [NO LINEAR INTERFERENSES], and those would be the above checked checkboxes.

I am joyous to assist you at any time.

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Find the least common denominator for these two rational expressions. B/b^2 -64 -7b/b^2+7b-8
san4es73 [151]

Answer:

The least common denominator is (b-8)(b+8)(b-1)

Step-by-step explanation:

We are given expression as

\frac{b}{b^2-64}-\frac{7b}{b^2+7b-8}

Firstly, we will factor both denominators

b^2-64=b^2-8^2=(b-8)(b+8)

b^2+7b-8=(b+8)(b-1)

so, we can plug it back

\frac{b}{(b-8)(b+8)}-\frac{7b}{(b+8)(b-1)}

First term denominator is

(b-8)(b+8)

Second term denominator is

(b+8)(b-1)

So,

Least common denominator will be

(b-8)(b+8)(b-1)

So, we get

LCD=(x-8)(x+8)(x-1)


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Answer:

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Step-by-step explanation:

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