Question

PLS HELP WILL GIVE BRAINLIEST :)

Answer 1

Step-by-step explanation:

the slope intercept form is

y = ax + b

"a" being the slope, "b" being the y- intercept (which is the y-value when x = 0).

the slope here :

in the table x is always increasing by 2.

and y is always investing by 1.

so, the slope is 1/2

the y-intercept :

we need to find the y-value for x = 0.

but we don't have a data point with x = 0 in the table.

so, we have to extend the structure of the table to the left.

x decreases by 2 (making it 0), and y decreases by 1 (making it -1).

therefore, the y- intercept (b) is -1.

and the line equation is

y = (1/2)x - 1

not sure about "the other method".

there is the point-slope form of the equation :

y - y1 = a(x - x1)

again with "a" begin the slope, and (x1, y1) being a point on the line.

if we get the y-intercept in the table, then this point is (0, y1).

and the equation would be

y - y1 = ax

in our case

y + 1 = (1/2)x

and another method ?

sometimes people write

nx + my = c

in our case starting with the original equation

y = (1/2)x - 1

2y = x - 2

-x + 2y = -2

x - 2y = 2