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Vesna [10]
2 years ago
6

Sorry forgot to post pictures of the question on last post (here there are)

Mathematics
1 answer:
Sedbober [7]2 years ago
4 0

Answer:

See below for answers and explanations

Step-by-step explanation:

<u>Problem 1</u>

<u />x=-3+2cos\theta,\:y=5+2sin\theta\\\\x+3=2cos\theta,\: y-5=2sin\theta\\\\(x+3)^2=4cos^2\theta,\: (y-5)^2=4sin^2\theta\\\\(x+3)^2+(y-5)^2=4cos^2\theta+4sin^2\theta\\\\(x+3)^2+(y-5)^2=4(cos^2\theta+sin^2\theta)\\\\(x+3)^2+(y-5)^2=4(1)\\\\(x+3)^2+(y-5)^2=4

Thus, the first option is correct. Trying all the other options will not get you the desired rectangular equation.

<u>Problem 2</u>

<u />x=3-6cos\theta,\: y=-2+3sin\theta\\\\x-3=-6cos\theta,\: y+2=3sin\theta\\\\\frac{x-3}{-6}=cos\theta,\: \frac{y+2}{3}=sin\theta\\ \\ \frac{(x-3)^2}{36}=cos^2\theta,\: \frac{(y+2)^2}{9}=sin^2\theta\\ \\ \frac{(x-3)^2}{36}+\frac{(y+2)^2}{9}=cos^2\theta+sin^2\theta\\\\ \frac{(x-3)^2}{36}+\frac{(y+2)^2}{9}=1

Therefore, the first option is correct. This equation is in the form of an ellipse with a horizontal major axis length of 12 (half is 6) and a vertical minor axis length of 6 (half is 3), with its center at (3,-2).

<u>Problem 3</u>

Not sure which equation needs to be used for this problem

<u>Problem 4</u>

<u />x=-7cos\theta ,\:y=5sin\theta\\\\-\frac{x}{7}=cos\theta,\: \frac{y}{5}=sin\theta\\ \\ \frac{x^2}{49}=cos^2\theta,\: \frac{y^2}{25}=sin^2\theta\\ \\\frac{x^2}{49}+\frac{y^2}{25}=cos^2\theta+sin^2\theta\\ \\ \frac{x^2}{49}+\frac{y^2}{25}=1

This equation is in the form of an ellipse with a horizontal major axis length of 14 (half is 7) and a vertical minor axis length of 10 (half is 5). See attached graph.

<u>Problem 5</u>

Eliminate the parameter:

x=-t^2-2,\:y=-t^3+4t\\\\x+2=-t^2\\\\-x-2=t^2\\\\\pm\sqrt{-x-2}=t\\\\y=-t^3+4t\\\\y=-(\pm\sqrt{-x-2})^3+4(\pm\sqrt{-x-2})

Attached below is the graph of the curve, which corresponds with the first option.

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Answer:

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Step-by-step explanation:

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7 0
3 years ago
Consider the vector x: x &lt;- c(2, 43, 27, 96, 18) Match the following outputs to the function which produces that output. Opti
Nookie1986 [14]

<u>Completed Question</u>

Outputs to be matched to the functions are:

  • 1,2,3,4,5
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Answer:

  • sort(x): 2, 18, 27, 43, 96
  • order(x): 1, 5, 3, 2, 4
  • rank(x) : 1, 4, 3, 5, 2
  • none of these :  1, 2, 3, 4, 5

Step-by-step explanation:

Given the vector x: x <- c(2, 43, 27, 96, 18)

<u>Sort</u>

In R, the sort(x)  function is used to arrange the entries in ascending or descending order. By default, R will sort the vector in ascending order.

Therefore, the output that matches the sort function is:

sort(x): 2, 18, 27, 43, 96

<u>Rank</u>

The rank function returns a vector with the "rank" of each value.

x <- c(2, 43, 27, 96, 18)

  • 2 has a rank of 1
  • 43 has a rank of 4
  • 27 has a rank of 3
  • 96 has a rank of 5
  • 18 has a rank of 2

Therefore, the output of rank(x)  is: 1, 4, 3, 5, 2

<u>Order</u>

When the function is sorted, the order function gives the previous location of each of the element of the vector.

Using the sort(x) function, we obtain: 2, 18, 27, 43, 96

In the vector: x <- c(2, 43, 27, 96, 18)

  • 2 was in the 1st position
  • 18 was in the 5th position
  • 27 was in the 3rd position
  • 43 was in the 2nd position
  • 96 was in the 4th position

Therefore, the output of order(x) is: 1, 5, 3, 2, 4

7 0
3 years ago
Pls pls help me please!!!!
BigorU [14]

Answer:

Move 6.2 units up

Step-by-step explanation:

(-5.4, 6.2)

The first coordinate is the x coordinate

Positive x moves to the right, negative x moves to the left

Move 5.4 units to the left

The second  coordinate is the y coordinate

Positive y moves to up, negative y moves down

Move 6.2 units up

4 0
3 years ago
The graph below shows the height of a tunnel f(x), in feet, depending on the distance from one side of the tunnel x, in feet:
denis23 [38]
Part A) x-intercepts simply show that when the value of the function is zero. Vertex coordinates show that when the function obtains its maximum value. When x=50, function obtains its maximum value and it's 75. The function is increasing in the interval (0, 50) and decreasing in the interval (50, 100). In regard to the height and distance of the tunnel, these numbers show that decreasing and increasing intervals are symmetric. Each number from the intervals has its own pair in the corresponding interval and they are located in the same distance from the midpoint (50,75)

Part B) In order to calculate the average rate of change, we can first write the function. Using the information about the x-intercept and the vertex coordinates, we find that our function is f(x)=-0.03x^{2}+3x.
Plugging 15 and 35 in x, we can find the values of the function, i.e. 
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Then, the average change is \frac{68.25-38.25}{35-15}=1.5
4 0
3 years ago
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So your answer would be 96.48 km/h

7 0
3 years ago
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