Using the unit circle, If the sine is negative, angle A must lie in either quadrant III or quadrant IV. Since we know that the cosine is positive, this only leaves quadrant IV

cos = adj/hyp

Using Pythagorean theorem,

$12^{2} +b^{2} = 13^{2}$

b = ±5 (we know its -5 since we know sinA is negative)

this means that the x coord is 12, and the y coord is -5

any proportion of these two numbers would work as an answer

e.g. (12, -5), (24,-10), (12/13, -5/13), are all valid answers

sinA = opp/hyp

sinA = -5/13

tanA = opp/adj

tanA = -5/12

5 0

1 year ago

(9x+1/2)+(7x-9 1/12)

miv72 [106K]

Step-by-step explanation:

Input Equation can be rewritten:

= (9*1/2)+(7*-91/12)

= (9/2)+(7*-91/12)

= (4.5)+(7*-91/12)

= 4.5+(7*-91/12)

= 4.5+(-637/12)

= 4.5+(-53.083333333333)

= 4.5+-53.083333333333

= 4.5-53.083333333333

= -48.583333333333

hope this helps!

5 0

2 years ago

Read 2 more answers

A factor tree for 61 that is not nothing

ddd [48]

False because the factor tree for 61 is 1 and 61

5 0

2 years ago

NEED URGENT HELP!

sp2606 [1]

(3,9)(5,15)
slope = (15 - 9) / (5 - 3) = 6/2 = 3

y = mx + b
slope(m) = 3
(3,9)...x = 3 and y = 9
sub and find b, the y int
9 = 3(3) + b
9 = 9 + b
9 - 9 = b
0 = b

so ur equation is : y = 3x + 0....can be written as y = 3x.

after 12 months...
y = 3x...x = 12
y = 3(12)
y = 36 inches

6 0

3 years ago