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3 years ago

Exercise 21.2

Mathematics

1 answer:

m_a_m_a [10]3 years ago

4 0

Answer:

1.y=3x+1

2.y=1/3x+2

3.y=-2x+5

4.y=4x

5.y=4x-4

6.y=-2x-5

Step-by-step explanation:

(i)

y=mx+c

10=(m)3+1

10=3m+1

10-1=3m

m =3

y=3x+1

And so on...

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Helpppp I’m so confused on this I appreciate it if you help!

tigry1 [53]

Example A: a/2

A fraction shows division as well! I’m not sure about the rest though....

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3 years ago

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Two hot dogs and a soda cost $3.25.if three hot dogs and a soda cost $4.50.what is the cost of two sodas?

kotegsom [21]

Answer: $1.50

Step-by-step explanation: 1. subtract the 3.25 from 4.50 to get a difference that is the price of the added hotdog 2. now that you know each hot dog cost $1.25 you can do 3.25 - 2(1.25) to get 0.75 which is the price of one soda. 3. You can no multiply $0.75 by two (the amount of sodas) to get the answer $1.50.

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3 years ago

PLEASE HELP!!

nasty-shy [4]

-5x+2y=6
2y=6+5x
y=5/2x + 6

x+3y=3
3y=3-x
y=-x/3+1

-2x+y=4
y=2x+4

4x+9y=-9
9y=-4x-9
y=-4/9x+1

Hope this helps.

6 0

3 years ago

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A gas station sells two grades of gasoline: regular and super. These are priced at $2.00 and $3.00 per gallon, respectively. Let

djyliett [7]

Answer:

(a) E(Y) = 4400

sd (Y) =225

(b) P(Y ≤ 4500) = 0.67003

Step-by-step explanation:

(a) Here we have

Y = 2·X₁ + 3·X₂

Therefore E(Y) = 2·E(X₁) + 3·E(X₂) = 2000 + 2400 = 4400

sd(Y) is given by

Variance Y = (sd (Y))² = 2²·(sd (X₁))² + 3²·(sd (X₂))²

= 4·8100 + 9·2025 = 50625

sd (Y) = √50625 = 225

(b) The probability that the revenue does not exceed 4500 is given by

P(Y ≤ 4500) = P(z ≤0.444)

z = $\frac{\overline{\rm x} - \mu} {\sigma /\sqrt{n} }$

z = $\frac{4500 - 4400} {225 /\sqrt{1} }$ = 0.444

Therefore from the normal distribution table, we have

P = 0.67003

Since the gas station sells 2 portions of X₁ to 3 portions of X₂

Therefore, the probability that the gas station sells more of X₁ is given by

₅C₀ × 2/5⁰×3/5⁵ = 0.07776

₅C₁ × 2/5¹×3/5⁴= 0.2592

₅C₂ × 2/5²×3/5³ = 0.3456

P (X₁ > X₂) = 1 - 0.68256 = 0.31744

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3 years ago

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Determine if the following are in proportion :

KATRIN_1 [288]

Step-by-step explanation:

The given numbers are : 32 , 48 , 140 , 120

First number is 32

Second number is 48

Third number is 140

Fourth number is 120

First number/second number :

$\dfrac{N_1}{N_2}=\dfrac{32}{48}\\\\=\dfrac{2}{3}\ ....(1)$

Third number/Fouth number :

$\dfrac{N_3}{N_4}=\dfrac{140}{120}\\\\=\dfrac{7}{6}\ ....(2)$

From equation (1) and (2) we can see that the ratio is not same. Hence, they are not in proportion.

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3 years ago