Answer:
If y(t) is the mass (in mg) remaining after t years, then y(t) = y(0) (0.5)^{t/T} = 400 (0.5)^{t /4}, where T is the half-life period and y(0) is the amount at t = 0 years (initial).
Then at t = 20:
y(20) = 400 (0.5)^{20 /4} = \text{12.5 mg}
Step-by-step explanation:
Answer:
10p coins does he have 102
Step-by-step explanation:
given data
saves= 10p coins and 20p coins
total = 17 pounds
to find out
how 10p coins does he have
solution
we consider here no of 20p coin = x
so equation will be here
3 × 10 x +20 x = 1700
30 x + 20 x = 1700
x = 34
so that
10p coins = 3 time × 34 = 102
20p coins = 34
so that 10p coins does he have 102
Thats... what people do here.
Answer:
Step-by-step explanation:
f(-1)= 1 - (-1)^2 + (-1)^3 = 1 - 1 - 1 = 0 - 1 = -1
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