Answer:
x = amount of pure acid to be added = 6.67ml
Step-by-step explanation:
George wishes to increase the percent of acid in 50ml of a 15% acid solution in water to 25% acid, how much pure acid must you add?
let
x = amount of pure acid to be added
15% of 50 + x = 25% of 50 + x
(0.15 * 50) + x = 0.25(50 + x)
7.5 + x = 12.5 + 0.25x
Collect like terms
x - 0.25x = 12.5 - 7.5
0.75x = 5
x = 5/0.75
x = 6.6666666666666
Approximately,
x = 6.67
x = amount of pure acid to be added = 6.67ml
F(x)=2x/(x-1)
Denominator cannot be equal 0.
x-1=0
x=1 is vertical asymptote.
To find horizontal asymptote
we need divide the coefficients before x
y=2x/x=2,because when x becomes really big (x---->∞) , value of 1 will not influence the result .
y=2 is horizontal asymptote
Answer:
12 months
Step-by-step explanation:
Theres an awful amount of needless information to get through.
Only the last paragrph is needed.
C(t) = 180 + 10t
C(t) = 25t
Set the equations equal
25t = 180 + 10t
Subtract 10t from both sides
15t = 180
Divide both sides by 15
t = 12
Answer:
6 degrees.
Step-by-step explanation:
