Answer:
25.6 units
Step-by-step explanation:
From the figure we can infer that our triangle has vertices A = (-5, 4), B = (1, 4), and C = (3, -4).
First thing we are doing is find the lengths of AB, BC, and AC using the distance formula:

where
are the coordinates of the first point
are the coordinates of the second point
- For AB:
![d=\sqrt{[1-(-5)]^{2}+(4-4)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%5B1-%28-5%29%5D%5E%7B2%7D%2B%284-4%29%5E2%7D)



- For BC:





- For AC:
![d=\sqrt{[3-(-5)]^{2} +(-4-4)^{2}}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%5B3-%28-5%29%5D%5E%7B2%7D%20%2B%28-4-4%29%5E%7B2%7D%7D)





Next, now that we have our lengths, we can add them to find the perimeter of our triangle:




We can conclude that the perimeter of the triangle shown in the figure is 25.6 units.
Answer: -4/7
Step-by-step explanation:
To find the slope, let's change the equation to slope-intercept form.
[subtract both sides by 4x]
[divide both sides by 7]

Now, we know the slope is -4/7.
Answer: The expression that represents Meg's finishing time in June is "y - 10".
The problem started with Meg running in April. She had a time in April and we called it "y".
Now, Meg ran again in June. In June, she did 10 seconds faster. So it makes since that we need to subtract 10 from her April time, "y". Therefore, the expression is simply "y - 10".
Let

be the point on the ground to with the 18 foot guy is anchored and

the point on the ground to with the 21 foot guy is anchored.
We can conclude that the <span>the two wires at the points where they are anchored are
21 feet apart. Check the procedures in the picture attached.</span>