Im pretty sure the answer is c; velocity is usually measure by a vector :)
Answer: A Radium
Explanation:
Thorium-232 is an alpha-emitting radionuclide, which decays to radium-228, which is a beta emitter with a half-life of about six years.
Newton's Third Law of Motion states that for every action there must exist an equal but opposite reaction.
This ultimately implies that, Newton's Third Law of Motion is a law based on action-reaction force pairs.
In this exercise, you're required to identify the action-reaction forces in the attached picture.
Under condition A, a boy is leaning against a wall;
- The force being exerted by the boy on the wall is a force of action.
- The force being exerted by the wall on the boy is a force of reaction.
Under condition B, a boy is jumping off a diving board.
- The force being exerted by the feet of the boy on the diving board is a force of action.
- The force being exerted by the diving board on the feet of the boy is a force of reaction.
Under condition C, a nail is being hammered into the wall.
- The force being exerted by the hammer on the nail is a force of action.
- The force being exerted by the nail on the hammer is a force of reaction.
Under condition D, a man is walking on a ground (floor).
- The force being exerted by the foot of the man on the ground (floor) is a force of action.
- The force being exerted by the ground (floor) on the foot of the man is a force of reaction.
Under condition E, a boy is holding a ball;
- The force being exerted by the hand of the boy on the ball is a force of action.
- The force being exerted by the ball on the hand of the boy is a force of reaction.
Read more: brainly.com/question/15170643
A) Metal expand upon heating. B) Alloys expand less upon heating than elemental metals. C) Alloys expand more upon heating than elementals metals. D) The rate of the expansion of metals is directly proportion to the temperature to which it is heated
Since the ladder is standing, we know that the coefficient
of friction is at least something. This [gotta be at least this] friction
coefficient can be calculated. As the man begins to climb the ladder, the
friction can even be less than the free-standing friction coefficient. However,
as the man climbs the ladder, more and more friction is required. Since he
eventually slips, we know that friction is less than what's required at the top
of the ladder.
The only "answer" to this problem is putting lower
and upper bounds on the coefficient. For the lower one, find how much friction
the ladder needs to stand by itself. For the most that friction could be, find
what friction is when the man reaches the top of the ladder.
Ff = uN1
Fx = 0 = Ff + N2
Fy = 0 = N1 – 400 – 864
N1 = 1264 N
Torque balance
T = 0 = N2(12)sin(60) – 400(6)cos(60) – 864(7.8)cos(60)
N2 = 439 N
Ff = 439= u N1
U = 440 / 1264 = 0.3481
