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2 years ago

Which body is found inside the solar system?

Physics

2 answers:

BaLLatris [955]2 years ago

7 0

A.moon (because the rest are space structures)

salantis [7]2 years ago

4 0

Answer:

moon

Explanation:

Moon

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What is the chemical formula for mercury(I) nitrate? Hgmc021-1.jpg(NOmc021-2.jpg) Hg(NOmc021-3.jpg)mc021-4.jpg Hgmc021-5.jpg(NOm

Anit [1.1K]

If you just type "What is the chemical formula for mercury(I) nitrate?" into google you get the answer but HG(NO3)2 is the correct one.
sorry no one helped you in time hope you passed anyway

8 0

4 years ago

Read 2 more answers

2) The horizontal and vertical components of the initial velocity of a football are 16 m/s and 20 m/s respectively. How long doe

ValentinkaMS [17]

Answer: 2.04 s

Explanation:

Let the initial velocity be v, Angle of projectile be

Then the horizontal component = v cos θ = 16 m/s

Vertical component of velocity = v sin θ = 20 m/s

Time taken to reach the highest point is half the time taken for total flight.

Time for total flight,

$t = \frac{2vsin \theta}{g}$

$t'=\frac{vsin \theta}{g} = \frac {20 m/s}{9.8 m/s^2} = 2.04 s$

Thus, the football takes 2.04 s to rise to the highest point of its trajectory.

5 0

3 years ago

determine whether the following equations are dimensionally correct if not how can you make them dimensionally correct 1 /2 mv2

serg [7]

Answer:

$1 /2 mv^{2} =mgh$

Explanation:

The correct equation follows the law of conservation of energy where kinetic energy is all transformed to potential energy, since we know that kinetic energy is expressed as

$1 /2 mv^{2}$ while potential energy is mgh where m is the mass of the object, v is the velocity or speed of the object, g is acceleration due to gravity and h is the vertical height. Therefore, relating the two equations we should have $1 /2 mv^{2} =mgh$

6 0

4 years ago

A 7.99 g sample of hcn is found to contain 0.296 g of h and 4.14 g of n.Find the mass of carbon in a sample of hcn with a mass o

Thepotemich [5.8K]

Answer:

Mass of C in 3.40 g of HCN =1.51 gram.

Explanation:

Mass of sample of HCN = 7.99 g

Mass of H in 7.99 g of HCN = 0.296 g

Mass of N in 7.99 g of HCN = 4.14 g

Mass of C in 7.99 g of HCN = (7.99-0.296-4.14) = 3.554 g

Now mass of HCN = 3.40 g

Mass of C in 3.40 g of HCN = $\frac{3.554}{7.99} *3.40 =1.51 g$

So mass of C in 3.40 g of HCN =1.51 gram.

3 0

3 years ago

A light beam is traveling through an unknown substance. When it exits that substance and enters into air, the angle of reflectio

bogdanovich [222]

Answer:

0.79

Explanation:

Using Snell's law, we have that:

n(1) * sin θ1 = n(2) * sinθ2

Where n(1) = refractive index of air = 1.0003

θ1 = angle of incidence

n(2) = refractive index of second substance

θ2 = angle of refraction

The angle of reflection through the unknown substance is the same as the angle of incidence of air. This means that θ1 = 32°

=> 1.0003 * sin32 = n(2) * sin42

n(2) = (1.0003 * sin32) / sin42

n(2) = 0.79

3 0

3 years ago

Read 2 more answers