Answer : The velocity of an electron is, 
Explanation :
According to de-Broglie, the expression for wavelength is,
and,
where,
p = momentum, m = mass, v = velocity
So, the formula will be:
.............(1)
where,
h = Planck's constant = 
= wavelength = 
m = mass of electron = 
v = velocity of electron = ?
Now put all the given values in formula 1, we get:
Thus, the velocity of an electron is,
The original Coulomb force between the charges is:
Fc=(k*Q₁*Q₂)/r², where k is the Coulomb constant and k=9*10⁹ N m² C⁻², Q₁ is the first charge, Q₂ is the second charge and r is the distance between the charges.
The magnitude of the force is independent of the sign of the charge so I can simply say they are both positive.
Q₁ is decreased to Q₁₁=(1/3)*Q₁=Q₁/3 and
Q₂ is decreased to Q₂₂=(1/2)*Q₂=Q₂/2.
New force:
Fc₁=(k*Q₁₁*Q₂₂)r², now we input the decreased values of the charge
Fc₁=(k*{Q₁/3}*{Q₂/2})/r², that is equal to:
Fc₁=(k*(1/3)*(1/2)*Q₁*Q₂)/r²,
Fc₁=(k*(1/6)*Q₁*Q₂)/r²
Fc₁=(1/6)*(k*Q₁*Q₂)/r², and since the original force is: Fc=(k*Q₁*Q₂)/r² we get:
Fc₁=(1/6)*Fc
So the magnitude of the new force Fc₁ with decreased charges is 6 times smaller than the original force Fc.
Answer:
Technician A is correct while Technician B is incorrect.
Explanation:
If Technician a says that that both slip rings must be insulated from the rotor shaft, then, technician a is correct.
If technician b says that at least one slip ring must be grounded to the shaft to provide a complete circuit for current flow, this statement is incorrect because each slip ring must be connected to one of the three phases of rotor windings. And the slip ring brushes are connected to a resistive device ( like a rheostat). When the slip rings turn with the rotor, the brushes will maintain constant contact with the rings and transfer the resistance to the rotor windings. Therefore, Technician A is correct while Technician B is incorrect.
The particles in diagram 3 move fast enough to break away from each other.
Answer:
B
Explanation:
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