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3 years ago

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I NEED HELP ASAP PLZZZZ HELP ME!!!! Activity log: Sit-and-Reach Test Date: Warm-up: Cool-down: Type of Activity: (Cardiovascular

, Muscular, or Flexibility) Description of Activity and Time: Intensity Level: (Moderate or Vigorous) Total Time: WRITER

1 answer:

liraira [26]3 years ago

3 0

Answer:

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Explanation:

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According to Newtons third law of motion when one object exerts a force on a second object what is true about the forces?

fomenos

Answer:

D.They are equal in magnitude and opposite in direction

Explanation:

Newton's third law states that the action force is always associated with a reaction force.
When a body 'A' exerts a force on body 'B', it is called the force of action.
When the body 'B' in turn resist the force of 'A' is called the reaction force. It is the reactive force acted upon by the body 'B' on 'A'.
This reaction force is equal in magnitude of the action force.
If the two bodies remain in the same horizontal line, the 'A' exerts a force in the direction towards 'B' and the body 'B' exerts a reaction force in the direction towards 'A'.
Hence, the two forces that are exerted by the bodies are equal in magnitude and opposite in direction.

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3 years ago

A soldier throws a grenade horizontally from the top of a cliff. Which of the following curves best describes the path taken by

Natasha_Volkova [10]

Answer:

4. Parabola

Explanation:

The motion of the flight of the grenade is a projectile motion, it's shape is best illustrated using a parabolic diagram.

It's not a circle as the path is not totally round.

It's not an ellipse as the path of motion is not a a completely bounded shape.

Its not a hyperbola as a hyperbola is an open curve with two branches.

Its a parabolic shape because a parabola has just one branch

7 0

4 years ago

EASY QUESTION!!! 20 POINTS!!!!!! PLZ ONLY CORRECT ANSWERS!!!

anyanavicka [17]

D) How fast you are moving

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4 years ago

A cart is moving at 55 m/s at an angle of 25° to the ground. Determine the horizontal component.

Elodia [21]

Answer:

<em>The horizontal component of the velocity is 49.85 m/s.</em>

Explanation:

<u>Rectangular Components of a Vector</u>

A 2D vector can be expressed in several forms. The rectangular form gives its two components, one for each axis (x,y). The polar form gives the components as the pair (r,θ) being r the magnitude and θ the angle.

When the magnitude and angle of the vector are given, the rectangular components are calculated as follows:

$v_x=v\cos\theta$

$v_y=v\sin\theta$

Where v is the magnitude of the vector and θ is the angle with respect to the x positive direction.

The cart is moving at v=55 m/s at θ=25°, thus:

$v_x=55\cos 25^\circ$

$v_x=49.85\ m/s$

The horizontal component of the velocity is 49.85 m/s.

7 0

3 years ago

A disk, with a radius of 0.25 m, is to be rotated like a merry-go-round through 800 rad, starting from rest, gaining angular spe

torisob [31]

Answer:

a) $T_{min} = 80\,s$

Explanation:

a) Let consider that disk accelerates and decelerates at constant rate. The expression for angular acceleration and deceleration are, respectively:

Acceleration

$\alpha_{1} = \frac{\omega_{max}^{2}}{2\cdot (400\,rad)}$

Deceleration

$\alpha_{2} = -\frac{\omega_{max}^{2}}{2\cdot (400\,rad)}$

Since angular acceleration and deceleration have same magnitude but opposite sign. Let is find the maximum allowed angular speed from maximum allowed centripetal acceleration:

$a_{r,max} = \omega_{max}^{2}\cdot r$

$\omega_{max} = \sqrt{\frac{a_{r,max}}{r} }$

$\omega_{max} = \sqrt{\frac{100\,\frac{m}{s^{2}} }{0.25\,m} }$

$\omega_{max} = 20\,\frac{rad}{s}$

Maximum magnitude of acceleration/deceleration is:

$\alpha = 0.5\,\frac{rad}{s^{2}}$

The least time require for rotation is:

$T_{min} = 2\cdot \left(\frac{20\,\frac{rad}{s} }{0.5\,\frac{rad}{s^{2}} } \right)$

$T_{min} = 80\,s$

3 0

3 years ago