I’ve always been failing since middle school. it’s bcs of quarantine that made me unmotivated. rn my grades are F’s D C and A . I should be paying attention but my phone just keeps me distracted lol.
        
                    
             
        
        
        
Answer:
81.3ohms
Explanation:
Resistance is known to provide opposition to the flow of electric current in an electric circuit.
Power dissipated by the computer is expressed as;
Power = current (I) × Voltage(V)
P = IV... (1)
Note that from ohms law, V = IR
I = V/R ... (2)
Substituting equation 2 into 1, we will have;
P = (V/R)×V
P = V²/R.. (3)
Given source voltage = 100V, Power dissipated = 123W
To get resistance R of the computer, we will substitute the given value into equation 3 to have
123 = 100²/R
R = 100²/123
R = 10,000/123
R = 81.3ohms
The resistance of the computer is 81.3ohms
 
        
                    
             
        
        
        
I say around 40% - 60%
https://www.dmv.ca.gov/portal/dmv/detail/teenweb/more_btn6/traffic/traffic
http://www.teendriversource.org/stats/support_teens/detail/57
http://www.rmiia.org/auto/teens/Teen_Driving_Statistics.asp
(I just corrected the question. Sorry if it is still incorrect.)
        
             
        
        
        
Work = Force x Distance = 500 x 4 = 2000 Nm = 2000 J
        
             
        
        
        
Answer:

The Magnitude of electric field is in the upward direction as shown directly towards the charge  .
.
Explanation:
Given:
- side of a square,  
- charge on one corner of the square,  
- charge on the remaining 3 corners of the square, 
<u>Distance of the center from each corners</u>


∴Distance of center from corners, 
Now, electric field due to charges is given as:

<u>For charge  we have the field lines emerging out of the charge since it is positively charged:</u>
 we have the field lines emerging out of the charge since it is positively charged:</u>

<u>Force by each of the charges at the remaining corners:</u>

<u> Now, net electric field in the vertical direction:</u>


<u>Now, net electric field in the horizontal direction:</u>
 
 
So the Magnitude of electric field is in the upward direction as shown directly towards the charge  .
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