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1 year ago

Hi i need help (again) i swear im smart

Mathematics

2 answers:

grigory [225]1 year ago

6 0

#2 is 30 pounds
STEP BY STEP EXPLANATION
If 9 is 30% then you multiply it by three and get 90% 9x3=27 and to get the last ten percent you divide the 9 by three and you get 3, then you add that to 27 and you get 30

ehidna [41]1 year ago

3 0

Answer:

The weight of an adult dog is 45 pounds.

Step-by-step explanation:

9 pounds is 20% of the adult weight. To get to 100%, you have to multiply 20 by 5. Multiply 9 by 5 and it will be 45. Sorry for answering late.

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If the discriminant is negative then the quadratic has

zepelin [54]

Answer:

No real solutions (or has two complex roots)

Step-by-step explanation:

The discriminant, b² - 4ac, is the expression (radicand ) of the quadratic equation:

$x = \frac{-b +/- \sqrt{b^{2}-4ac} }{2a}$ .

The value of the discriminant determines the nature and the number of solutions given by the quadratic equation.

A discriminant with a negative value (or b² - 4ac < 0 ) means that the quadratic equation has no real solutions or two complex solutions. Quadratic equations with a negative discriminant also have no x-intercepts; thus, its graph will not cross the x-axis.

4 0

2 years ago

miles bought 3.75 acres of land in 1993 in 1997 he bought enough land to double his property then in 2001 miles was forced to se

MariettaO [177]

3.45 acres
solution :
3.75+3.75= 7.5
7.5-2.9 = 4.6
4.6×.25= 1.15
4.6-1.15= 3.45

6 0

2 years ago

I’m not quite sure how to answer this question.

Marina CMI [18]

When two shapes are mathematically similar, that means that all their sides are in a proportion.

We know the sieds of EH and AD, and so we can find the proportion of the shapes using these two sides.

EH/AD = 6/9 = 2/3

The ratio of EFGH to ABCD is 2:3

Now we have to find BC.

Becuase they're in proportion, we can form this equation:

$\frac{8}{BC}$ = $\frac{2}{3}$

Cross multiply:

24 = 2*BC

Divide both sides by 2:

BC = 12 cm

Good luck!

6 0

2 years ago

Suppose that each child born is equally likely to be a boy or a girl. Consider a family with exactly three children. Let BBG ind

Gemiola [76]

Answer:

(a)

$S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}$

(b)

$1\ girl = \{GBB, BBG, BGB\}$

$P(1\ girl) = 0.375$

ii.

$Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}$

$P(Atleast\ 2 \ girls) = 0.5$

iii.

$No\ girl = \{BBB\}$

$P(No\ girl) = 0.125$

Step-by-step explanation:

Given

$Children = 3$

$B = Boys$

$G = Girls$

Solving (a): List all possible elements using set-roster notation.

The possible elements are:

$S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}$

And the number of elements are:

$n(S) = 8$

Solving (bi) Exactly 1 girl

From the list of possible elements, we have:

$1\ girl = \{GBB, BBG, BGB\}$

And the number of the list is;

$n(1\ girl) = 3$

The probability is calculated as;

$P(1\ girl) = \frac{n(1\ girl)}{n(S)}$

$P(1\ girl) = \frac{3}{8}$

$P(1\ girl) = 0.375$

Solving (bi) At least 2 are girls

From the list of possible elements, we have:

$Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}$

And the number of the list is;

$n(Atleast\ 2 \ girls) = 4$

The probability is calculated as;

$P(Atleast\ 2 \ girls) = \frac{n(Atleast\ 2 \ girls)}{n(S)}$

$P(Atleast\ 2 \ girls) = \frac{4}{8}$

$P(Atleast\ 2 \ girls) = 0.5$

Solving (biii) No girl

From the list of possible elements, we have:

$No\ girl = \{BBB\}$

And the number of the list is;

$n(No\ girl) = 1$

The probability is calculated as;

$P(No\ girl) = \frac{n(No\ girl)}{n(S)}$

$P(No\ girl) = \frac{1}{8}$

$P(No\ girl) = 0.125$

7 0

2 years ago

What is the solution of this system of linear equations? y = 2x - 3 2x =y-3 Click on the coordinate grid below to graph the line

MrRa [10]

Answer:

the solution is the purpose I love the best part is to watch it s dark blue in a bit of a drive and we will be there by the money for it and only and not the case then we are good

4 0

3 years ago