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AURORKA [14]
3 years ago
5

Answer this questions for 40 points! :) it is attached.

Mathematics
2 answers:
telo118 [61]3 years ago
5 0
Im so confused by this question but my only guess would be that since a coin is a 1/2 chance getting it heads twice is 1/2 * 1/2 which is 1/4 so the person who best they can get 2 heads in a row pays 1/4 of the bet being 5 dollars because 1/4 of 20 is 5 and the person who bets that they can't get two heads pays 15 dollars because that is 3/4 of the bet

tldr: 1/4 chance to get heads pays 1/4 of bet 5$
3/4 chance not to get heads pays 3/4 of bet 15$
irina [24]3 years ago
4 0

Answer:

$5

Step-by-step explanation:

You need to calculate the expected value of this game.

There are 4 equally likely outcomes:

1. heads-heads

2. heads-tails

3. tails-heads

4. tails-tails

The winnings for each outcome is:

1. heads-heads $20

2. heads-tails $0

3. tails-heads $0

4. tails-tails $0

Each outcome has a 0.25 probability of occurring.

The expected value is the sum of the products of the probability of each outcome and its winnings

expected value = 0.25 * $20 + 0.25 * $0 + 0.25 * $0 + 0.25 * $0

expected value = $5

To be a fair game, each play should cost $5.

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Someone please.. help me in this please I don’t want to fail it..please
igomit [66]

Answer:

So it wants you to first find the mean (average) of the data set, then find the distance everything is from the mean (average).

Step-by-step explanation:

3+5+9+14+16+18= 65

65 divided by the amount of numbers you put in (6) = 10.83 rounded to the nearest hundreth

So now we know the mean (average) now we need to see how far away each number is from the mean (average).10.83-3 is 7.83. 10.83-5 is 5.83. 10.83-9 is 1.83. 10.83-14 is -14.17, but -14.17 would be a normal 14.17 because it wants the absolute value. 10.3-16 is -5.17 (of course keep it as a positive), and finally 10.83-18 is -7.17 as a positive. Now for the mean absolute value of the data they likely mean from 0, so it would be 10.83.

Hope it helped and wasn't too confusing :)

7 0
3 years ago
you deposit 10000 into a bank account. the account pays 4 annual interest compounded quarterly. find the balance after 5 years.
Ann [662]
<h3>Answer: 12,201.90 dollars</h3>

You may need to delete the comma if you are entering this result into a computer system.

=====================================================

Work Shown:

P = 10,000 = deposit

r = 0.04 = decimal form of 4% interest rate

n = 4 = we're compounding 4 times a year

t = 5 years

-------------

A = P*(1+r/n)^(n*t) .... compound interest formula

A = 10,000*(1+0.04/4)^(4*5)

A = 12,201.9003994797

A = 12,201.90

After 5 years, there is $12,201.90 in the account.

This is assuming you do not deposit any more money, and it also assumes that you don't take any money out during the 5 year timespan either.

8 0
3 years ago
A random sample of 28 statistics tutorials was selected from the past 5 years and the percentage of students absent from each on
SVEN [57.7K]

Answer:

Step-by-step explanation:

Hello!

X: number of absences per tutorial per student over the past 5 years(percentage)

X≈N(μ;σ²)

You have to construct a 90% to estimate the population mean of the percentage of absences per tutorial of the students over the past 5 years.

The formula for the CI is:

X[bar] ± Z_{1-\alpha /2} * \frac{S}{\sqrt{n} }

⇒ The population standard deviation is unknown and since the distribution is approximate, I'll use the estimation of the standard deviation in place of the population parameter.

Number of Absences 13.9 16.4 12.3 13.2 8.4 4.4 10.3 8.8 4.8 10.9 15.9 9.7 4.5 11.5 5.7 10.8 9.7 8.2 10.3 12.2 10.6 16.2 15.2 1.7 11.7 11.9 10.0 12.4

X[bar]= 10.41

S= 3.71

Z_{1-\alpha /2}= Z_{0.95}= 1.645

[10.41±1.645*(\frac{3.71}{\sqrt{28} } )]

[9.26; 11.56]

Using a confidence level of 90% you'd expect that the interval [9.26; 11.56]% contains the value of the population mean of the percentage of absences per tutorial of the students over the past 5 years.

I hope this helps!

7 0
4 years ago
Question 1 of 25 What is the median of this set of data values? 10.14, 15, 17, 20, 21, 22.25 O A. 17 B. 20 C. 18 D. 185​
Reil [10]

Answer:

18

Step-by-step explanation:

3 0
3 years ago
What is the square root of 1/25
SashulF [63]
\sqrt{ \frac{1}{25} }= \frac{ \sqrt{1} }{ \sqrt{25} }= \frac{1}{5}
7 0
4 years ago
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