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kumpel [21]
2 years ago
13

Subtract, need help again! thanks a lot.​

Mathematics
1 answer:
vesna_86 [32]2 years ago
8 0

\quad\qquad\qquad\huge\underline{\boxed{\sf Aηswer☂ }}

Here's the solution ~

<h3># First </h3>

\qquad \sf  \dashrightarrow \:  \sqrt{8}  -  \sqrt{2}

\qquad \sf  \dashrightarrow \: ( \sqrt{2 \times 2 \times 2}  )-  \sqrt{2}

\qquad \sf  \dashrightarrow \:  2\sqrt{ 2}  -  \sqrt{2}

\qquad \sf  \dashrightarrow \:  \sqrt{ 2}

<h3># Second </h3>

\qquad \sf  \dashrightarrow \:    \sqrt[3]{24} -  \sqrt[3]{3}

\qquad \sf  \dashrightarrow \:    (\sqrt[3]{2 \times 2 \times 2 \times 3}) -  \sqrt[3]{3}

\qquad \sf  \dashrightarrow \:    2\sqrt[3]{3} -  \sqrt[3]{3}

\qquad \sf  \dashrightarrow \:    \sqrt[3]{3}

<h3># Third </h3>

\qquad \sf  \dashrightarrow \:    \sqrt[]{125}  -  \sqrt{45}

\qquad \sf  \dashrightarrow \:    \sqrt[]{5 \times 5 \times 5}  -  \sqrt{3 \times 3 \times 5}

\qquad \sf  \dashrightarrow \:    5 \: \sqrt[]{5 }  -  3\sqrt{ 5}

\qquad \sf  \dashrightarrow \:    2 \: \sqrt[]{5 }

<h3># Fourth</h3>

\qquad \sf  \dashrightarrow \:     \: \sqrt[5]{96 }  -   \sqrt[5]{3}

\qquad \sf  \dashrightarrow \:     \: \sqrt[5]{2  {}^{5}  \times 3}  -   \sqrt[5]{3}

\qquad \sf  \dashrightarrow \:     \: 2\sqrt[5]{3}  -   \sqrt[5]{3}

\qquad \sf  \dashrightarrow \:     \: \sqrt[5]{3}

<h3 /><h3># Fifth</h3>

\qquad \sf  \dashrightarrow \:     \: \sqrt[]{75}   -  \sqrt{27}

\qquad \sf  \dashrightarrow \:     \: \sqrt[]{3 \times 5 \times 5}   -  \sqrt{3 \times 3  \times3}

\qquad \sf  \dashrightarrow \: 5 \sqrt{3} - 3 \sqrt{3}

\qquad \sf  \dashrightarrow \: 2 \sqrt{3}

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