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Dimas [21]
2 years ago
13

Help please!! Thank you!! :)

Mathematics
1 answer:
Naddik [55]2 years ago
5 0

Answer:

  A.  m^2+7m+10=0

Step-by-step explanation:

This is a problem in pattern matching, and in substituting a variable for a pattern.

  (x^2+3)^2 +7x^2 +21 = -10 . . . . . . given

  (x^2 +3)^2 +7(x^2 +3) = -10 . . . . . factor the last two terms

  m^2 +7m = -10 . . . . . . . . . . . . subsitute m for x^2 +3

  m^2 +7m +10 = 0 . . . . . . . . add 10 to both sides; matches A

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Step-by-step explanation:

Vertical asymptote can be Identites if there is a factor only in the denominator. This means that the function will be infinitely discounted at that point.

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Disclaimer if you see something like this

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x=5 won't be a vertical asymptote, it will be a hole because it in the numerator and denominator.

Horizontal:

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Remember a constant can be represent by

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For example,

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2 =  2 \times {x}^{0}

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x =  {x}^{1}

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\frac{1 \times  {x}^{0} }{ {x}^{1} }

Look at the degrees, since the numerator has a smaller degree than the denominator, the denominator will grow larger than the numerator as x gets larger, so since the larger number is the denominator, our y values will approach 0.

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